擅长:python、mysql、java
<p>以下是我的解决方案:</p>
<pre><code>def time_after_time(time_a, time_b):
time_a_min = time_a.hour * 60 + time_a.minute
time_b_min = time_b.hour * 60 + time_b.minute
out_min = time_b_min - time_a_min
if out_min < 0:
out_min += 24 * 60
return datetime.time(out_min / 60, out_min % 60)
</code></pre>
<p>你可以在<a href="http://codepad.org/QMXWjZXR" rel="nofollow">codepad.org</a>上测试它。你知道吗</p>