如何从单个列表返回两个单独的列表？

Question

如果您在此处有此列表：

[25, 8, 22, 9] 

如何让程序创建两个单独的列表，并打印它们？一个应该包含所有小于20的数字，另一个需要包含所有大于20的数字。最终的打印结果应该这样显示：[8, 9]，[25, 22]

Answer 1

def print_split_list(raw_list, split_value):
    lower_list = [v for v in raw_list if v < split_value]
    upper_list = [v for v in raw_list if v >= split_value]
    print lower_list, upper_list

print_split_list([25, 8, 22, 9], 20)  # => [8, 9] [25, 22]

Answer 2

>>> predicates = lambda x:x<20, lambda x:x>20
>>> print [filter(pred, [25, 8, 22, 9]) for pred in predicates]
[[8, 9], [25, 22]]

Answer 3

使用list comprehensions：

>>> L = [25, 8, 22, 9]
>>> [x for x in L if x < 20]
[8, 9]
>>> [x for x in L if x > 20]
[25, 22]