我得到的错误NoReverseMatch在包括网址名称网址.py

2024-04-18 06:23:40 发布

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我得到了以下错误，尽管包括在url名称网址.py地址：

Reverse for 'upload' with arguments '()' and keyword arguments '{}' not found.0 pattern(s) tried: []

我已经给的网址名称为'上传'中网址.py 最初主页.html应该发布到“upload”，这是我包含的文件视图：

url(r'^upload/',FileView.as_view(),name='upload')

视图.py

def initial(request):
    return render(request,'display/home.html')

class FileView(FormView):
    template_name = 'display/upload.html'
    form_class = FileForm
    success_url = 'success/'


    def form_valid(self, form):
    file_upload = FileModel(
    fileup=self.get_form_kwargs().get('files')['fileup'])

    #results = FileForm.objects.filter(Q(name__icontains=your_search_query)     | Q(startdate__icontains=your_search_query) |   Q(enddate__icontains=your_search_query)).order_by('pub_date')

     file_upload.save()
    self.id = file_upload.id
    return render_to_response('display/success.html')
    return HttpResponseRedirect(self.get_success_url())

    def get_success_url(self):
    return reverse('file_upload', kwargs={'pk': self.id})

def redirect(request):
    return render(request,"display/success.html")
...

网址.py

from django.conf.urls import url

from . import views

from display.views import FileView

urlpatterns = [
    url(r'^start/', views.initial,name='home'),
    url(r'^upload/',FileView.as_view(),name='upload'),
    url(r'^success/',views.redirect,name='success'),
    #url(r'^upload',views.upload,name='upload'),
    ]

模板 主页.html

<!DOCTYPE html>
<html>
    <head>
        <title>CSV FILE UPLOAD</title>
    </head>

<body>
    <form enctype="multipart/form-data" method="POST" action="{% url 'upload' %}">
        {% csrf_token %}



        <input type="submit" name="submit"  />
    </form>
</body>


Tags： namepyselfformurlreturnrequestdef
1条回答
网友
1楼 · 发布于 2024-04-18 06:23:40

这个urls.py看起来不像根url配置。。。可能根url conf中缺少include？你知道吗

示例：

urlpatterns = [
    url(r'^display/', include('display.urls', namespace='display')),
]

如果它是这样包含的，您应该将uploadurl引用为：

<form enctype="multipart/form-data" method="POST" action="{% url 'display:upload' %}">

其他可能的解决方案，请尝试在url regex的末尾添加$：

from django.conf.urls import url

from . import views

from display.views import FileView

urlpatterns = [
    url(r'^start/$', views.initial,name='home'),
    url(r'^upload/$',FileView.as_view(),name='upload'),
    url(r'^success/$',views.redirect,name='success'),
]

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