为什么“finally:return”不传播未处理的异常？

Question

为什么函数不引发异常？显然没有被抓住。你知道吗

def f():
    try:
        raise Exception
    finally:
        return "ok"

print(f())  # ok

Answer 1

从documentation：

A finally clause is always executed before leaving the try statement, whether an exception has occurred or not. [...] The finally clause is also executed “on the way out” when any other clause of the try statement is left via a break, continue or return statement.

也就是说，在一个函数中，finally子句总是返回。即使没有发生异常：

def f():
    try:
        return 'OK'
    finally:
        return 'Finally'

f() # returns 'Finally'