如何在单引号内获取字符串，但忽略“'s”和“'t”？

Question

我想检索单引号内的字符串，例如在以下句子中：

Play 'My lady's on fire' by Ty Segall

我要检索：

My lady's on fire

我想忽略带有's和't的单词，比如“不要”和“女士”：

我试过这个：

re.findall(r"\s\'.*?\'", user_input)

但是，我得到了：

[ 'My lady']

我想得到：

[My lady's on fire]

Answer 1

根据您的要求，一个备选方案（可能不是最有效的）是：

\'(?:(?!\'[^st]).)*\'

从本质上讲，你一直在使用字符，直到你找到一个以'开头的序列，而不是紧跟着一个s或t。你知道吗

如果你需要更一般的情况下，你考虑词的边界，然后看看其他答案。你知道吗

Answer 2

^{}

\B assert position where \b does not match
' matches the character ' literally (case sensitive)
Non-capturing group (?:[^']*(?:'\b)?)+
+ Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed (greedy)
Match a single character not present in the list below [^']*
* Quantifier — Matches between zero and unlimited times, as many times as possible, giving back as needed (greedy)
' matches the character ' literally (case sensitive)
Non-capturing group (?:'\b)?
? Quantifier — Matches between zero and one times, as many times as possible, giving back as needed (greedy)
' matches the character ' literally (case sensitive)
\b assert position at a word boundary: (^\w|\w$|\W\w|\w\W)
' matches the character ' literally (case sensitive)

Answer 3

您可以使用这个正则表达式->；\b\s'(.*?)(?=\'\s|\'$) 你可以在https://pythex.org/上测试它

Python代码：

import re user_input = "Play 'My lady's on fire' by Nipsey Hussle Play 'My lady's on fire'" print(re.findall(r"\b\s'(.*?)(?=\'\s|\'$)",user_input))