以下算法的更Pythonic方法

Question

我用更合乎逻辑的方法改变了最后的结构：

{'state1': {'city1': ['dict1', 'dict2']}, 'state2': {'City2': ['dict3']}}

代码是：

dir_dict = {}
for one in objects:
    state = one.dir.city.state.name
    city ​​= one.dir.city.name
    address = one.dir.address
    if state not in dir_dict:
        dir_dict[state] = {}
    if city not in dir_dict[state]:
        dir_dict[state][city] = []
    dir_dict[state][city].append(address)

我仍然实现代码@Eric

Answer 1

from collections import defaultdict
dir_dict = defaultdict(lambda: defaultdict(set))
for x in objects:
     dir_dict[x.state][x.city].add(x.address)

dir_list = dir_dict.keys()