我正在使用Stanford dependency parser
,我得到以下句子的输出
I shot an elephant in my sleep
>>>python dep_parsing.py
[((u'shot', u'VBD'), u'nsubj', (u'I', u'PRP')), ((u'shot', u'VBD'), u'dobj', (u'elephant', u'NN')), ((u'elephant', u'NN'), u'det', (u'an', u'DT')), ((u'shot', u'VBD'), u'nmod', (u'sleep', u'NN')), ((u'sleep', u'NN'), u'case', (u'in', u'IN')), ((u'sleep', u'NN'), u'nmod:poss', (u'my', u'PRP$'))]
但是,我希望编号的标记作为输出,就像it is here
nsubj(shot-2, I-1)
root(ROOT-0, shot-2)
det(elephant-4, an-3)
dobj(shot-2, elephant-4)
case(sleep-7, in-5)
nmod:poss(sleep-7, my-6)
nmod(shot-2, sleep-7)
这是我的密码。你知道吗
from nltk.parse.stanford import StanfordDependencyParser
stanford_parser_dir = 'stanford-parser/'
eng_model_path = stanford_parser_dir + "stanford-parser-models/edu/stanford/nlp/models/lexparser/englishRNN.ser.gz"
my_path_to_models_jar = stanford_parser_dir + "stanford-parser-3.5.2-models.jar"
my_path_to_jar = stanford_parser_dir + "stanford-parser.jar"
dependency_parser = StanfordDependencyParser(path_to_jar=my_path_to_jar, path_to_models_jar=my_path_to_models_jar)
result = dependency_parser.raw_parse('I shot an elephant in my sleep')
dep = result.next()
a = list(dep.triples())
print a
我怎么能有这样的输出?你知道吗
编写一个遍历树的递归函数。作为第一步,试着给单词分配数字。你知道吗
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