python递增字符循环

2024-03-28 11:30:47 发布

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好的,我正在努力创建一个增量列表循环。你知道吗

希望实现一个循环,该循环执行以下操作: 循环遍历字符集1 a-Z。如果没有找到匹配项,则添加到循环中,以便aa ZZ,依此类推。似乎找不到一个好方法来做循环。你知道吗

import itertools
result = "password"
charset1 = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
charset2 = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z','A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
charcount = 1

while i != result
    finalchar = charset1[-1]
    finalset = charset1[-1] * charcount
    for check in 

Tags: 方法import列表passwordresult增量aaitertools
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1楼 · 发布于 2024-03-28 11:30:47

您可以使用itertools.productrepeat参数作为模板:

from string import ascii_letters
from itertools import product

for i in range(1, 3): # do 1 and 2 chars
    chars = product(ascii_letters, repeat=i)
    for combo in chars:
        print(''.join(combo))

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