好吧,所以你可能会觉得这很愚蠢,是的,我是一个初学者,当谈到编程,但有可能这样做吗?我的朋友试图用一些额外的代码来完成它,但它甚至无法启动。我很肯定我把清单弄乱了,所以我很感激你的提示和更正:)
import time
character_list = [a,b,c,d] # creating list with characters
buttons_list = [pygame.K_a,pygame.K_b,pygame.K_c,pygame.K_d]#creating list with key-events
while True:
millis = int(round(time.time()*1000))
hours = int(round( millis / 3600000))
# print a letter to the screen with character_list[hours]
necessary_button = buttons_list[hours]
if event.type == pygame.KEYDOWN:
if event.key == necessary_button:
# do some awesome stuff
这是我朋友给我的密码:
import pygame
pygame.init()
display_width = 1600
display_height = 900
white = (255,255,255)
black = (0,0,0)
red = (255,0,0)
green = (0,155,0)
game_display = pygame.display.set_mode((display_width,display_height))
pygame.display.set_caption('AYYLMAO')
smallfont = pygame.font.SysFont("comicsansms",25)
def text_objects(text,color,size):
if size == "small":
textSurf = smallfont.render(text, True, color)
return textSurf, textSurf.get_rect()
def message_to_screen(msg, color, y_displace = 0,size = "small"):
textSurf, textRect = text_objects(msg,color,size)
textRect.center = (display_width/2), ( display_height/2)+y_displace
game_display.blit(textSurf, textRect)
def gameLoop():
game_display.fill(white)
character_list = ["a","b","c","d","e"]
buttons_list = [pygame.K_a, pygame.K_b, pygame.K_c, pygame.K_d, pygame.K_e]
message_to_screen(character_list[0], red)
pygame.display.update()
necessary_button = buttons_list[0]
if event.type == pygame.KEYDOWN:
if event.key == necessary_button:
message_to_screen(GG, red)
if event.key == pygame.K_ESCAPE:
pygame.QUIT()
gameLoop()
这至少会把“a”打印到屏幕上,但我得到一个错误:“第38行,在gameLoop中 如果事件类型== pygame.KEYDOWN键: NameError:未定义全局名称“event”。“我希望这不仅仅是我犯的另一个愚蠢的错误:D
目前没有回答
相关问题 更多 >
编程相关推荐