伙计们,我刚开始学Python。。我对此一无所知。我把这张单子和字典有关的问题。。它向我显示了一条错误消息。 错误O/P和代码如下所示。。你知道吗
Error:
Traceback (most recent call last):
File "python", line 48, in <module>
File "python", line 45, in get_class_average
File "python", line 25, in get_average
TypeError: list indices must be integers, not st
lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}
def average(numbers):
total = float(sum(numbers))/len(numbers)
return total
def get_average(student):
homework = average(student['homework'])
quizzes = average(student['quizzes'])
tests = average(student['tests'])
return 0.1*homework + \
0.3*quizzes + \
0.6*tests
def get_letter_grade(score):
if score>=90:
return "A"
elif score>=80:
return "B"
elif score>=70:
return "C"
elif score>=60:
return "D"
else:
return "F"
get_letter_grade(get_average(lloyd))
def get_class_average(students):
results=[];
results.append(get_average(students));
return average(results)
sts=[lloyd,alice,tyler];
get_class_average(sts)
您的
students
变量是一个包含三个学生的列表(呃。。。三本字典)。你知道吗当您执行
results.append(get_average(students));
操作时,您将该列表传递给get_average
方法,在一个名为student
的参数中(但在get_average
函数中,该函数仍然是一个列表,因为参数的名称是不相关的)然后,在
get_average
中,您尝试以student['homework']
的形式访问列表。因为student
参数是一个列表,所以会出现错误。你知道吗你可能想这样做?你知道吗
编辑(根据OP对该答案的评论):
我想好的资源可以是this和this(还有更多的Googling python lists dictionaries)
results.append(get_average(students))
应该在列表上迭代,因为get_average
需要一个dict
。替换为:或者简单地说:
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