从列表中的值向列表中的dict添加键

Question

如果dict包含某个键，如何从另一个列表中的值向列表中的dict添加键？你知道吗

我有一张单子。这些dict要么只包含一个键（“review”），要么包含两个键（“review”和“response”）。当dict包含键response时，我想添加两个键，其中包含两个列表中的值。你知道吗

data = [{'response': 'This is a response',
         'review': 'This is a review'},
        {'review': 'This is only a review'},
        {'response': 'This is also a response',
         'review': 'This is also a review'}]
date = ['4 days ago',
        '3 days ago']
responder = ['Manager',
             'Customer service']

我尝试了以下方法，但是因为对于每个包含键“response”的dict，我只想从每个列表的值中添加1，所以我不知道如何做到这一点。你知道吗

for d in data:
    if 'response' in d:
        for i in date:
            d['date'] = i
        for i in responder:
            d['responder'] = i

输出告诉我，它当然只添加列表的最后一个值，因为我在列表上循环。我怎样才能解决这个问题？你知道吗

[{'date': '3 days ago',
  'responder': 'Customer service',
  'response': 'This is a response',
  'review': 'This is a review'},
 {'review': 'This is only a review'},
 {'date': '3 days ago',
  'responder': 'Customer service',
  'response': 'This is also a response',
  'review': 'This is also a review'}]

Answer 1

您可以为日期和响应者列表创建迭代器，然后在if语句中调用next()，从列表中获取下一项

data = [{'response': 'This is a response', 
         'review': 'This is a review'}, 

        {'review': 'This is only a review'}, 

        {'response': 'This is also a response', 
         'review': 'This is also a review'}]

date = ['4 days ago', '3 days ago']
responder = ['Manager', 'Customer service']

d_iter = iter(date)
r_iter = iter(responder)

for d in data:
    if 'response' in d:
        d['date'] = next(d_iter)
        d['responder'] = next(r_iter)

print(data)
>> [
{'date': '4 days ago', 
 'review': 'This is a review', 
 'responder': 'Manager', 
 'response': 'This is a response'},  

{'review': 'This is only a review'}, 

{'date': '3 days ago', 
 'review': 'This is also a review', 
 'responder': 'Customer service', 
 'response': 'This is also a response'}
]

Answer 2

您可以尝试这样做，但要小心，因为列表上的response数应该等于列表的长度：

d_r = zip(date, responder)

for d in data:
    if 'response' in d:
            d['date'], d['responder'] = next(d_r)
print(data)

Answer 3

我认为您正在尝试添加两个以日期为键的条目，并且值不同。在字典里你不能有重复的键。这就是为什么在for循环字典只更新了一个日期键条目和一个响应者条目之后