错误:函数外的“return”
为什么??你知道吗
def get_all_students(self):
database = open(self.database_path, 'r')
list_of_students = list()
for idx, l in enumerate(database.readlines()):
params = list()
params.append(idx)
params += l.split(self.data_delimiter)
student = Student(*self.item_un_escape(params))
list_of_students.append(student)
return list_of_students
编辑:我会发布这个类的其余部分,我很确定它的缩进是正确的。似乎找不到错误,我敢打赌这可能是愚蠢的事情。抱歉,第一次用python编写代码,但是这个错误已经困扰了我大约一个小时了!哈哈
Edit2:这是一个错误参数附加(idx)说意外的缩进?你知道吗
from student import Student
database_path = 'C:/Users/Alan/Desktop/flask/flask/app/database'
class Database(object):
data_delimiter = ','
@staticmethod
def escape_new_lines(value):
if type(value) == str:
value = value.replace('\n', '@n-nl@')
value = value.replace('\r', '@r-nl@')
return value
@staticmethod
def un_escape_new_lines(value):
if type(value) == str:
value = value.replace('@n-nl@', '\n')
value = value.replace('@r-nl@', '\r')
return value
def __init__(self, database_path=database_path):
self.database_path = database_path
def get_all_students(self):
database = open(self.database_path, 'r')
list_of_students = list()
for idx, l in enumerate(database.readlines()):
params = list()
params.append(idx)
params += l.split(self.data_delimiter)
student = Student(*self.item_un_escape(params))
list_of_students.append(student)
return list_of_students
你发布的代码很好。可能的错误是在return语句之前缺少缩进。编辑:正如@Anonymous在评论中指出的,另一种可能是您将制表符缩进和空格缩进混合在一起。检查你的压痕。你知道吗
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