python重新匹配（）未返回预期结果

Question

我正在尝试使用重新匹配地址：

revenue = "Revenue;;Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,190,140,1926,14,143;Coffee,325,19,293,1491,162;Water,682,14,852,56,659;Milk,829,140,609,120,87;;Expenses;;Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,120,65,890,54,430;Coffee,300,10,23,802,235;Water,50,299,1290,12,145;Milk,67,254,89,129,76;;"
revenue = re.match(r"(?<=Revenue;;).*(?=;E)", file_content)
print(revenue)

但是它返回None。你知道吗

我在regex101.com上测试了正则表达式，它提供了所需的匹配，即Revenue;;后面的文本和;Expenses前面的文本：

Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,190,140,1926,14,143;Coffee,325,19,293,1491,162;Water,682,14,852,56,659;Milk,829,140,609,120,87;

因此，我假设我的python实现有问题，但是，我在python regex文档中找不到任何帮助我的信息。在python2和python3上都试过了。你知道吗

我会做错什么

Answer 1

使用re.search

例如：

import re

revenue = "Revenue;;Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,190,140,1926,14,143;Coffee,325,19,293,1491,162;Water,682,14,852,56,659;Milk,829,140,609,120,87;;Expenses;;Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,120,65,890,54,430;Coffee,300,10,23,802,235;Water,50,299,1290,12,145;Milk,67,254,89,129,76;;"
revenue = re.search(r"(?<=Revenue;;).*(?=;E)", revenue)
print(revenue.group())

输出：

Item,Johnver,Vanston,Danbree,Vansey,Mundyke;Tea,190,140,1926,14,143;Coffee,325,19,293,1491,162;Water,682,14,852,56,659;Milk,829,140,609,120,87;