防止按键排队

2024-04-25 08:44:11 发布

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我在做一个小项目,有一个树莓皮和一个2.8英寸的电容触摸屏。我是python新手,需要防止多次按下按钮排队。所需的行为是UI在执行上一个按钮按下时忽略任何按钮按下。这是我的密码:

from Tkinter import *
import RPi.GPIO as GPIO
import time

#pin assignments
A=11
B=13
C=15
D=12
E=16
FAN=8

GPIO.setwarnings(False)
GPIO.setmode(GPIO.BOARD)
GPIO.setup(A, GPIO.OUT)
GPIO.setup(B, GPIO.OUT)
GPIO.setup(C, GPIO.OUT)
GPIO.setup(D, GPIO.OUT)
GPIO.setup(E, GPIO.OUT)
GPIO.setup(FAN, GPIO.OUT)

class App:
  def fanOn(self):
    GPIO.output(FAN,True)
  def fanOff(self):
    GPIO.output(FAN,False)
  def btnClicked(self,atty):
    GPIO.output(atty,True)
    self.fanOn()
    time.sleep(5)
    GPIO.output(atty,False)
    self.fanOff()
  def __init__(self, master):
    frame = Frame(master)
    frame.pack()
    self.buttonA = Button(frame, text="Fire A", fg="red", command=lambda: self.btnClicked(A))
    self.buttonA.pack(side=LEFT)
    self.buttonB = Button(frame, text="Fire B", fg="red", command=lambda: self.btnClicked(B))
    self.buttonB.pack(side=LEFT)
    self.buttonC = Button(frame, text="Fire C", fg="red", command=lambda: self.btnClicked(C))
    self.buttonC.pack(side=LEFT)
    self.buttonD = Button(frame, text="Fire D", fg="red", command=lambda: self.btnClicked(D))
    self.buttonD.pack(side=LEFT)
    self.buttonE = Button(frame, text="Fire E", fg="red", command=lambda: self.btnClicked(E))
    self.buttonE.pack(side=LEFT)

root = Tk()
app = App(root)
root.mainloop()

谢谢你的帮助!你知道吗


Tags: lambdatextselfgpiosetupbuttonredout