我对Python非常陌生,事实上,编程也是如此。 我有两个元组列表,它们之间没有重复(列表是通过列表理解消除重复元组的结果)。 我想在包含的元组(new/deleted/changed)中找到交集,并创建了以下示例:
包含组、项和计数器的元组列表:
list1 = [("fruits","apple",1),("fruits","banana",1),("legumes","bean",3),("meats","deadbeef",1),("meats","pork",2)]
list2 = [("fruits","apple",2),("fruits","mango",4),("legumes","pea",3),("plants","rose",1)]
我的目标是这样的:
*Report*:
New group: "plants" with item "rose", count 2
Deleted group: "meats" with items "deadbeef", count 1, "pork", count 2
New item in group "fruits": "mango", count 4
New item in group "legumes": "pea", count 3
Deleted item in group "fruits": "banana", count 1
Deleted item in group "legumes": "bean", count 3
Changed item in group "fruits": item "apple" new count 2, old count 1
任何帮助都是非常感谢的,因为我完全被困在如何甚至开始:(
我甚至不确定我是否选择了正确的数据结构,所以我对每一个提示都完全开放。你知道吗
谢谢你
乔尔
你可以把打印状态,因为你需要只是取代通行证打印“无论”
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