擅长:python、mysql、java
<p><strong>更新</strong></p>
<p>我希望这对你有用。</p>
<pre><code>a = ['a', 'b', 'b', 'c', 'a', 'a', 'a', 'a', 'c', 'c', 'c']
previo = None
counter = 0
temp_l, checked = [], []
for item in a:
if item != previo:
temp_l = []
if not temp_l or item == previo:
temp_l.append(item)
previo = item
if len(temp_l) >= 2 and item not in checked:
counter += 1
checked.append(item)
previo = item
print counter
</code></pre>
<p>再见</p>