Python：如何让Python计算一个和以确保输入是正确的？

Question

我想让python问10个问题，用户必须输入他们的答案。不过，我也希望python通过使用下面的代码来说明这是否正确，但这不起作用，只会进入下一个问题。有人能告诉我为什么吗？或者我需要改变什么？另外，我该如何使用我拥有的变量和while循环让这个ask 10问题具体化呢？你知道吗

import time
import random
question = 0
score = 0
name = input("What is your full name?")
print ("Hello " + name, "welcome to The Arithmetic Quiz")
time.sleep(2)
operand1 = list(range(2, 12))
operators = ["+"]
operand2 = list(range(2, 12))

while question < 10:
    user_answer=int(input(str(random.choice(operand1)) + random.choice(operators) + str(random.choice(operand2))))
    if operators=='+':
        expected_answer==operand1 + operand2
        if user_answer==expected_answer:
            print('This is correct!')
            score = score + 1
            question = question + 1
            time.sleep(2)
        else:
            print('This is incorrect!')
            question = question + 1
            time.sleep(2)

Answer 1

以下是解决您问题的方法：

import time
import random

question = 0
score = 0
name = input("What is your full name?")
print ("Hello " + name, "welcome to The Arithmetic Quiz")
time.sleep(2)
operand1 = list(range(2, 12))
operand2 = list(range(2, 12))

while question < 10:
    num1 = random.choice(operand1)
    num2 = random.choice(operand2)
    print(str(num1) + "+" + str(num2))
    user_answer = int(input())
    expected_answer = int(num1) + int(num2)
    if user_answer == expected_answer:
        print('This is correct!!')
        score = score + 1
        question = question + 1
    else:
        print('This is incorrect!!')
        question = question + 1

print("\nYour score is " + str(score))

这里不需要operands变量，而是可以将+运算符作为字符串本身传递。 另外，由于操作数1和操作数2是作为列表传递的，而不是作为int传递的，所以预期的\u answer变量无法解析求和