a的分支json.loads文件（）已加载词典作为新词典

Question

我对json库的知识有些限制，但是我找不到任何地方访问文件分支的方法。我将使用http://json.org/example.html中的JSON示例文件来形成这个问题

{
    "glossary": {
        "title": "example glossary",
        "GlossDiv": {
            "title": "S",
            "GlossList": {
                "GlossEntry": {
                    "ID": "SGML",
                    "SortAs": "SGML",
                    "GlossTerm": "Standard Generalized Markup Language",
                    "Acronym": "SGML",
                    "Abbrev": "ISO 8879:1986",
                    "GlossDef": {
                        "para": "A meta-markup language, used to create markup languages such as DocBook.",
                        "GlossSeeAlso": ["GML", "XML"]
                    },
                    "GlossSee": "markup"
                }
            }
        }
    }
}

我做了以下工作。 编写了预处理函数：

def PreProc(JSONFile):
    with open(JSONFile, 'r') as myfile:
        data = myfile.read()
    myfile.close()
    return data

并称之为：

path = 'C:\\path\\file.json'
Data = json.loads(PreProc(path))

此时：

print(type(Data.keys()))
print(Data.items())
print(type(Data.items()))

退货：

<class 'dict_keys'>
dict_items([('glossary', {'title': 'example glossary', 'GlossDiv': .......
<class 'dict_items'>

如何通过关键字访问JSON文件的任何分支或子分支，并以字符串或字典格式返回它？
我实际的JSON文件包含复杂对象的列表，这些对象中也包含对象的列表，这就是为什么我宁愿这样做，避免过于复杂的对象表示、jsondeconders和对象钩子，我就是绕不过去。 我正在寻找一种解决方案，其工作原理类似于以下概念函数：

def Recursion(Dict,Structure):
    #Attempts to find a keyword that marks the begging of a complex ctructure in a given dictionary
    try:
        for key in Dict.keys():
            #Parses through all the keys of the dictionary
            try:
                if key==Structure:
                    NewDict = key.items()
                    return NewDict
                else:
                    #Set the dictionary that will be used in the recursion as all the items in the 'key' branch
                    dict = key.items()
                Recursion(dict, Structure)
            except:
                continue
    except:
        print("Needed Structure Not Found in Dictionary ", Dict, " !") 

函数的调用抛出和AttributeError，因为在第一个递归步骤中，它试图将dict_items解析为dict。理想情况下，声明：

BranchedData = Recursion(Data,'GlossList')  
print(BranchedData)

应输出（作为字符串或dict）：

{
    "GlossEntry": {
    "ID": "SGML",
    "SortAs": "SGML",
    "GlossTerm": "Standard Generalized Markup Language",
    "Acronym": "SGML",
    "Abbrev": "ISO 8879:1986",
    "GlossDef": {
        "para": "A meta-markup language, used to create markup languages such as DocBook.",
        "GlossSeeAlso": ["GML", "XML"]
    },
    "GlossSee": "markup"
    }
}  

编辑：澄清问题，调整代码，以保持清晰和错误