值错误:不支持连续多输出

2024-04-23 11:04:25 发布

您现在位置:Python中文网/ 问答频道 /正文

我想在一个拥有5000行和6个特性的数据集上运行几个回归类型(Lasso、Ridge、ElasticNet和SVR)。线性回归。使用GridSearchCV进行交叉验证。代码是广泛的,但这里有一些关键部分:

def splitTrainTestAdv(df):

    y = df.iloc[:,-5:]  # last 5 columns
    X = df.iloc[:,:-5]  # Except for last 5 columns


    #Scaling and Sampling

    X = StandardScaler().fit_transform(X)

    X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.8, random_state=0)


return X_train, X_test, y_train, y_test

def performSVR(x_train, y_train, X_test, parameter):



    C = parameter[0]
    epsilon = parameter[1] 
    kernel = parameter[2]

    model = svm.SVR(C = C, epsilon = epsilon, kernel = kernel)
    model.fit(x_train, y_train)



return model.predict(X_test)  #prediction for the test

def performRidge(X_train, y_train, X_test, parameter):

    alpha = parameter[0]

    model = linear_model.Ridge(alpha=alpha, normalize=True) 
    model.fit(X_train, y_train)



return model.predict(X_test)  #prediction for the test

MODELS = {
    'lasso': (
        linear_model.Lasso(),
        {'alpha': [0.95]}
    ),
    'ridge': (
        linear_model.Ridge(),
        {'alpha': [0.01]}
        ),
    )
}


def performParameterSelection(model_name, feature, X_test, y_test, X_train, y_train):


    print("# Tuning hyper-parameters for %s" % feature)
    print()

    model, param_grid = MODELS[model_name]
    gs = GridSearchCV(model, param_grid, n_jobs= 1, cv=5, verbose=1, scoring='%s_weighted' % feature)


    gs.fit(X_train, y_train) 


    print("Best parameters set found on development set:")

    print(gs.best_params_)
    print()
    print("Grid scores on development set:")
    print()
    for params, mean_score, scores in gs.grid_scores_:
        print("%0.3f (+/-%0.03f) for %r"
          % (mean_score, scores.std() * 2, params))

    print("Detailed classification report:")
    print()
    print("The model is trained on the full development set.")
    print("The scores are computed on the full evaluation set.")

    y_true, y_pred = y_test, gs.predict(X_test)
    print(classification_report(y_true, y_pred))

soil = pd.read_csv('C:/training.csv', index_col=0)
soil = getDummiedSoilDepth(soil)
np.random.seed(2015)
soil = shuffleData(soil)
soil = soil.drop('Depth', 1)

X_train, X_test, y_train, y_test = splitTrainTestAdv(soil)


scores = ['precision', 'recall']

for score in scores:




    for model in MODELS.keys():

        print '####################'
        print model, score
        print '####################'
        performParameterSelection(model, score, X_test, y_test, X_train, y_train)

您可以假设所有必需的导入都已完成

我得到这个错误,不知道为什么:

ValueError                                Traceback (most recent call last)

在() 18打印模型,分数 19打印 --->;20性能参数选择(型号、分数、X_测试、y_测试、X_训练、y_训练) 21岁

<ipython-input-27-304555776e21> in performParameterSelection(model_name,  feature, X_test, y_test, X_train, y_train)
     12     # cv=5 - constant; verbose - keep writing
     13 
---> 14     gs.fit(X_train, y_train) # Will get grid scores with outputs from ALL models described above
     15 
     16         #pprint(sorted(gs.grid_scores_, key=lambda x: -x.mean_validation_score))

C:\Users\Tony\Anaconda\lib\site-packages\sklearn\grid_search.pyc in fit(self, X, y)

C:\Users\Tony\Anaconda\lib\site-packages\sklearn\metrics\classification.pyc in _check_targets(y_true, y_pred)
     90     if (y_type not in ["binary", "multiclass", "multilabel-indicator",
     91                        "multilabel-sequences"]):
---> 92         raise ValueError("{0} is not supported".format(y_type))
     93 
     94     if y_type in ["binary", "multiclass"]:

ValueError: continuous-multioutput is not supported

我对Python还很陌生,这个错误让我困惑。当然,这不应该是因为我有6个特征。我试着遵循标准的内置函数。

求求你,救命


Tags: intestalphagsformodelparametertrain
1条回答
网友
1楼 · 发布于 2024-04-23 11:04:25

首先让我们复制这个问题。

首先导入所需的库:

import numpy as np
import pandas as pd 
from sklearn.preprocessing import StandardScaler
from sklearn.cross_validation import train_test_split
from sklearn import linear_model
from sklearn.grid_search import GridSearchCV

然后创建一些数据:

df = pd.DataFrame(np.random.rand(5000,11))
y = df.iloc[:,-5:]  # last 5 columns
X = df.iloc[:,:-5]  # Except for last 5 columns
X_train, X_test, y_train, y_test = train_test_split(X, y, test_size=0.8, random_state=0)

现在,我们可以复制错误并查看不复制错误的选项:

运行正常

gs = GridSearchCV(linear_model.Lasso(), {'alpha': [0.95]}, n_jobs= 1, cv=5, verbose=1)
print gs.fit(X_train, y_train) 

这不是

gs = GridSearchCV(linear_model.Lasso(), {'alpha': [0.95]}, n_jobs= 1, cv=5, verbose=1, scoring='recall')
gs.fit(X_train, y_train) 

事实上,这个错误和上面的完全一样;“不支持连续多输出”。

如果你考虑召回措施,它是与二进制或分类数据有关的-关于这些数据,我们可以定义诸如误报等。至少在我复制您的数据时,我使用了连续数据,而回忆只是没有定义。如果你使用默认的分数,它会起作用,正如你在上面看到的。

因此,您可能需要查看您的预测并理解它们为什么是连续的(即使用分类器而不是回归)。或者用不同的分数。

另外,如果只使用一组(列的)y值运行回归,仍然会得到一个错误。这一次它更简单地说“不支持连续输出”,即问题是对连续数据使用回调(或精度)(无论是否为多输出)。

相关问题 更多 >