谷歌自定义设备动作在树莓派谷歌助手上出现错误

2024-04-19 00:52:38 发布

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我在我的Raspberry Pi 3上创建了一个google助手,我正在尝试创建一个自定义的设备操作来最终打开我的车库门。它所做的就是在这个时间点播放一个LED。你知道吗

这是我的操作.json文件:

{
    "manifest": {
        "displayName": "Garage door",
        "invocationName": "Garage door",
        "category": "PRODUCTIVITY"
    },
    "actions": [
        {
            "name": "me.custom.actions.GarageDoor",
            "availability": {
                "deviceClasses": [
                    {
                        "assistantSdkDevice": {}
                    }
                ]
            },
            "intent": {
                "name": "me.custom.intents.GarageDoor",
                "trigger": {
                    "queryPatterns": [
                        "open the garage door",
                        "close the garage door"
                    ]
                }
            },
            "fulfillment": {
                "staticFulfillment": {
                    "templatedResponse": {
                        "items": [
                            {
                                "simpleResponse": {
                                    "textToSpeech": "Okay"
                                }
                            },
                            {
                                "deviceExecution": {
                                    "command": "me.custom.commands.GarageDoor"
                                }
                            }
                        ]
                    }
                }
            }
        }
    ],
    "types": []
}

但是当我运行命令时,我得到了一个错误:

INFO:root:Transcript of user request: "open the garage door".
INFO:root:Playing assistant response.
WARNING:root:Error during command execution
Traceback (most recent call last):
  File "/home/pi/assistant-sdk-python/google-assistant-sdk/googlesamples/assistant/grpc/device_helpers.py", line 94, in dispatch_command
    self.handlers[command](**params)
TypeError: gdoor() argument after ** must be a mapping, not NoneType

这是我的处理程序:

@device_handler.command('me.custom.commands.GarageDoor')
    def gdoor(*args):
        print(args)
        global g_open
        if g_open:
            GPIO.output(18, 0)
            g_open = 0
        else:
            GPIO.output(18, 1)
            g_open = 1

我在玩*args,看看它是否修复了任何东西-它没有。我把包名改为custom只是为了隐私。我很困惑。感谢您的帮助!你知道吗

谢谢!你知道吗


Tags: thenameactionscustomgoogleargsrootopen
1条回答
网友
1楼 · 发布于 2024-04-19 00:52:38

看看the sample code,函数签名似乎有点不同,因为它直接添加了参数。你知道吗

@device_handler.command('com.example.commands.BlinkLight')
def blink(speed, number):
    logging.info('Blinking device %s times.' % number)
    delay = 1
    if speed == "SLOWLY":
        delay = 2
    elif speed == "QUICKLY":
        delay = 0.5
    for i in range(int(number)):
        logging.info('Device is blinking.')
        time.sleep(delay)

查看操作包,您似乎没有提供任何与命令实现相关的操作。如the sample所示:

{
    "deviceExecution": {
        "command": "com.example.commands.BlinkLight",
        "params": {
            "speed": "$speed",
            "number": "$number"
        }
    }
}

如果没有任何参数,它可能根本无法映射任何函数。你知道吗

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