使用具有两个for循环的列表理解从两个列表中选择元素

Question

我有以下作业问题：

做一个列表理解，使用I和R的元素，只选择I和R的非负整数元素。注意：为此，应使用两个For循环。

列表

I = [-1, 0, 1, 2]
R = [2.7818, 0.0, -3.14159]

所需输出

[0, 1, 2]

谢谢你

考特尼

另外，我唯一能想到的回答问题的方法就是把这两个列表合并成一个这样：

NonNeg=[i+R中的i表示i，如果（i>；=0和isinstance（i，int））]

Answer 1

我找到了另一个解决办法问题。问题答案不可归纳，但符合教授为我们设定的学习目标：如何在列表理解中使用嵌套for循环。

Since there is only 1 value in list R that is greater than 0, the result of the list comprehension's first iteration is the only result returned

numbers = [(i,r) for i in I for r in R if(r>0)]
result: [(-1, 2.7818), (0, 2.7818), (1, 2.7818), (2, 2.7818)]

For each tuple in the list i, for each element j in the tuple return elements that are greater than zero and an integer

NonNeg = [j for i in numbers for j in i if(j >= 0 and j%1==0)]
result:[0, 1, 2]

A more generalizable is solution would be what I originally posted:
NonNeg2 = [i for i in I+R if(i >= 0 and isinstance(i,int))]
result:[0, 1, 2]

Answer 2

list1 = [1, 2, 3]
list2 = [2.0, 4, 10.5]
d = [x for x in list1+list2 if isinstance(x,int)]
print(d)

说明：

使用+运算符组合列表