当窗口服务启动时会发生什么？

Question

我正在用python编写一个windows服务，并使用pyinstaller将其打包成一个可执行文件。python脚本将包含带有必要重写方法的服务子类，以及用于某些套接字通信和显示简单消息框的MessageServer类。由于Windows中的交互服务限制，我将MessageServer分开。我想弄清楚的是，当您从GUI或CLI（net start）启动服务时会发生什么？它是只执行带有start参数的服务的.exe，还是只访问其中的一部分代码？你知道吗

我会张贴我使用的代码，但请记住，这是远远不够的地方，我想为真正的东西。。。只是用它来测试一些想法。你知道吗

import win32serviceutil
import win32service
import win32event
import servicemanager
import win32timezone
import win32api
import win32con

import sys
import time
import random

import multiprocessing

svc_name = "testSvc"
TIMEOUT = 6000


class TesterService(win32serviceutil.ServiceFramework):
    _svc_name_ = svc_name
    _svc_display_name_ = "test service"
    _svc_description_ = "This service is for testing purposes"

    def __init__(self, args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)

    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)

    def SvcDoRun(self):
        global sm
        while True:
            stop_signal = win32event.WaitForSingleObject(self.hWaitStop, TIMEOUT)

            try:
                if stop_signal == win32event.WAIT_OBJECT_0:
                    break
                else:
                    if sm == 0:
                        sm = 1
            except RuntimeError as details:
                print(details)


class MessageServer(object):
    def __init__(self):
        self._messages_ = ["msg-1", "msg-2", "msg-3", "msg-4", "msg-5"]
        self._serve_msg_(self._messages_)

    def _serve_msg_(self, msgs):
        t = 0
        while t < 36:
            time.sleep(6)
            t += 6
            win32api.MessageBox(
                None,
                msgs[random.randint(0, 4)],
                "test message box",
                win32con.MB_ICONHAND
            )


class MsgSrvProcess(multiprocessing.Process):
    def __init__(self, name="Ptest"):
        multiprocessing.Process.__init__(self)
        self.name = name

    def run(self):
        MessageServer()


sm = 0
if __name__ == "__main__":
    multiprocessing.freeze_support()

    if len(sys.argv) == 1:
        servicemanager.Initialize(svc_name, None)
        servicemanager.PrepareToHostSingle(TesterService)
        servicemanager.StartServiceCtrlDispatcher()

    else:
        win32serviceutil.HandleCommandLine(TesterService)
    c = 0
    while c < 18:
        c += 6
        if sm == 1:
            p1 = MsgSrvProcess()
            p1.start()
            p1.join()
        else: sm = 1
        time.sleep(6)
    print("exiting")