如何使用以前字典中的键和值创建字典？

Question

我需要创建一个字典，它的键是以前创建的字典中的值。我以前的字典是：

{100000: (400, 'Does not want to build a %SnowMan %StopAsking', ['SnowMan', 'StopAsking'], [100, 200, 300], [400, 500]), 
100001: (200, 'Make the ocean great again.', [''], [], [400]), 
100002: (500, "Help I'm being held captive by a beast!  %OhNoes", ['OhNoes'], [400], [100, 200, 300]), 
100003: (500, "Actually nm. This isn't so bad lolz :P %StockholmeSyndrome", ['StockholmeSyndrome'], [400, 100], []), 
100004: (300, 'If some random dude offers to %ShowYouTheWorld do yourself a favour and %JustSayNo.', ['ShowYouTheWorld', 'JustSayNo'], [500, 200], [400]), 
100005: (400, 'LOLZ BELLE.  %StockholmeSyndrome  %SnowMan', ['StockholmeSyndrome', 'SnowMan'], [], [200, 300, 100, 500])}

这本词典的形式是{key:（id，string，tags，likes，dislikes）} 我需要创建一个字典，它的键是第一个字典中的标记，值是id和包含标记的字符串，以字典的形式呈现。你知道吗

例如，如果我们使用标记'SnowMan'，新字典应该如下所示：

{'SnowMan': {400: ['Does not want to build a %SnowMan %StopAsking', 'LOLZ BELLE.  %StockholmeSyndrome  %SnowMan']}}

或者，如果我们使用标签'StockholmeSyndrome'，新字典应该如下所示：

{'StockholmeSyndrome': {
        500: ["Actually nm. This isn't so bad lolz :P %StockholmeSyndrome"], 
        400: ['LOLZ BELLE.  %StockholmeSyndrome  %SnowMan']}}

最后，新字典需要将上一个字典中的所有标记都包含为键，包括没有标记的事件。你知道吗

我真的被困在这个问题上了，有人能给我一些指导吗？你知道吗

Answer 1

使用^{}可以迭代并附加到嵌套字典结构中的列表：

from collections import defaultdict

dd = defaultdict(lambda: defaultdict(list))
for id_, text, tags, likes, dislikes in d.values():
    for tag in tags:
        dd[tag][id_].append(text)

print(dd)

defaultdict(<function __main__.<lambda>>,
            {'': defaultdict(list, {200: ['Make the ocean great again.']}),
             'JustSayNo': defaultdict(list,
                         {300: ['If some random dude offers to %ShowYouTheWorld do yourself a favour and %JustSayNo.']}),
             'OhNoes': defaultdict(list,
                         {500: ["Help I'm being held captive by a beast!  %OhNoes"]}),
             'ShowYouTheWorld': defaultdict(list,
                         {300: ['If some random dude offers to %ShowYouTheWorld do yourself a favour and %JustSayNo.']}),
             'SnowMan': defaultdict(list,
                         {400: ['Does not want to build a %SnowMan %StopAsking',
                           'LOLZ BELLE.  %StockholmeSyndrome  %SnowMan']}),
             'StockholmeSyndrome': defaultdict(list,
                         {400: ['LOLZ BELLE.  %StockholmeSyndrome  %SnowMan'],
                          500: ["Actually nm. This isn't so bad lolz :P %StockholmeSyndrome"]}),
             'StopAsking': defaultdict(list,
                         {400: ['Does not want to build a %SnowMan %StopAsking']})})

defaultdict是dict的一个子类，因此通常不需要进一步的操作。但是，如果需要常规的dict对象，可以使用递归函数：

def default_to_regular_dict(d):
    """Convert nested defaultdict to regular dict of dicts."""
    if isinstance(d, defaultdict):
        d = {k: default_to_regular_dict(v) for k, v in d.items()}
    return d

res = default_to_regular_dict(dd)

print(res)

{'': {200: ['Make the ocean great again.']},
 'JustSayNo': {300: ['If some random dude offers to %ShowYouTheWorld do yourself a favour and %JustSayNo.']},
 'OhNoes': {500: ["Help I'm being held captive by a beast!  %OhNoes"]},
 'ShowYouTheWorld': {300: ['If some random dude offers to %ShowYouTheWorld do yourself a favour and %JustSayNo.']},
 'SnowMan': {400: ['Does not want to build a %SnowMan %StopAsking',
   'LOLZ BELLE.  %StockholmeSyndrome  %SnowMan']},
 'StockholmeSyndrome': {400: ['LOLZ BELLE.  %StockholmeSyndrome  %SnowMan'],
  500: ["Actually nm. This isn't so bad lolz :P %StockholmeSyndrome"]},
 'StopAsking': {400: ['Does not want to build a %SnowMan %StopAsking']}}

Answer 2

这个怎么样？你知道吗

keys = ['name', 'last_name', 'phone_number', 'email']
dict2 = {x:dict1[x] for x in keys}

Answer 3

在审查了你的要求后，我用下面的代码更新了我以前的帖子。我相信这就是你想要达到的目标。唯一需要的导入是来自collections模块的OrderedDict。你知道吗

from collections import OrderedDict
from pprint import PrettyPrinter as pp


str_tag_dict = {}
for v in d.values():
    str_tag_dict[v[1]] = v[2]

def same_tags_and_ids(str1, str2):
    dd = {str1:str_tag_dict[str1], 
          str2:str_tag_dict[str2]}
    tag = []
    v = dd[str1]
    for vv in v:
        for ks in dd.keys():
            if vv in dd[ks]:
                tag.append(vv)
                for tg in tag:
                    if tag.count(tg) > 1:
                        return tg
    return None

ordp = OrderedDict(sorted(d.items()))
def same_tags_diff_ids():
    x = []
    y = []
    my_str = []
    for v in ordp.values():
        x.append(v[2][0])
        x.append(v[0])
        x.append(v[1])
        for i in x:
            if x.count(i) > 1 and type(i) == str:
                y.append(i)
    for i in range(len(x)):
        if x[i] == list(set(y))[0]:
            my_str.append({list(set(y))[0]:{x[i + 1]:[x[i + 2]]}})
    d={}
    k1, v1 = list(my_str[0][list(my_str[0])[0]].items())[0]
    k2, v2 = list(my_str[1][list(my_str[1])[0]].items())[0]
    d.update({list(my_str[0].keys())[0]:{k1:v1, k2:v2}}) 
    if not d == None:
        return d
    else:
        return None
dup_tag_str = same_tags_diff_ids()

for k, v in ordp.items():
    del d[k]
    for tag in v[2]:
        d[tag] = {v[0]:[v[1]]}

ordp = OrderedDict(sorted(d.items()))
ids= [list(v.keys())[0] for v in ordp.values()]
strs= [list(v.values())[0][0] for v in ordp.values()]

x = 0
for n in range(len(ordp)):
    tmp_keys = []
    for k, v in ordp.items():
        if not strs[x] == list(v.values())[0][0]:
            if ids[x] == list(v.keys())[0]:
                key = same_tags_and_ids(strs[x], list(v.values())[0][0])
                if not key == None:
                    tmp_keys.append(key)
                    if tmp_keys.count(key) == 1:
                        continue
                    else:
                        ordp[key][list(v.keys())[0]].append(strs[x])
    x += 1
dx = dup_tag_str
dy = dict(ordp)
dy.update(dx)
pp().pprint(dy)               

输出：

 {'': {200: ['Make the ocean great again.']},
 'JustSayNo': {300: ['If some random dude offers to %ShowYouTheWorld do '
                 'yourself a favour and %JustSayNo.']},
 'OhNoes': {500: ["Help I'm being held captive by a beast!  %OhNoes"]},
 'ShowYouTheWorld': {300: ['If some random dude offers to %ShowYouTheWorld 
  do yourself a favour and %JustSayNo.']},
 'SnowMan': {400: ['LOLZ BELLE.  %StockholmeSyndrome  %SnowMan',
               'Does not want to build a %SnowMan %StopAsking']},
 'StockholmeSyndrome': {400: ['LOLZ BELLE.  %StockholmeSyndrome %SnowMan'],
                        500: ["Actually nm. This isn't so bad lolz :P "
                          '%StockholmeSyndrome']},
 'StopAsking': {400: ['Does not want to build a %SnowMan %StopAsking']}}