Python，要列出和排序的对象

Question

我把我所有的对象都添加到一个列表中，但是它们没有被排序，我想通过LevelNo对列表中的条目进行排序，所以1然后2。你知道吗

我得到的错误是

Traceback (most recent call last):
  File "pagerduty.py", line 143, in <module>
    OnCallData = OnCallData.sort(key=operator.itemgetter('LevelNo'))
NameError: name 'operator' is not defined

我现在的代码是

from operator import itemgetter
class User(object):
    __attrs = ['Policy','Level', 'LevelNo', 'StartDate', 'EndDate', 'StartTime',
               'EndTime', 'Name', 'Mobile']

    def __init__(self, **kwargs):
        for attr in self.__attrs:
            setattr(self, attr, kwargs.get(attr, None))

    def __repr__(self):
        return ', '.join(
            ['%s: %r' % (attr, getattr(self, attr)) for attr in self.__attrs])  


OnCallData = [] 
for UserItem in objPolicyData['users']:   
    UserData = User()     
    UserData.Name = UserItem['name']
    UserData.Mobile = UserMobile = getUserMobile(UserItem['id']) 
    for OnCall in UserItem['on_call']:    
        UserPolicy = OnCall['escalation_policy'] 
        PolicyName = UserPolicy['name']
        if PolicyName.lower().find('test') == -1:      
            UserData.Policy = PolicyName
            UserData.LevelNo = OnCall['level']
            UserData.Level = getLevel(OnCall['level'])
            UserData.StartDate = getDate(OnCall['start'])
            UserData.EndDate = getDate(OnCall['end'])
            UserData.StartTime = getTime(OnCall['start'])
            UserData.EndTime = getTime(OnCall['end'])    
            OnCallData.append(UserData)

OnCallData = sorted(OnCallData, key=itemgetter('LevelNo'))  

样本数据为

[
Policy: u'Network Team', Level: 'Backup On Call Engineer', LevelNo: 2, StartDate: 'Monday 02 May', EndDate: 'Monday 09 May', StartTime: '09:00AM', EndTime: '09:00AM', Name: u'John Smith', Mobile: u'07XXX', 
Policy: u'System Administator Team', Level: 'Primary On Call Engineer', LevelNo: 1, StartDate: 'Tuesday 03 May', EndDate: 'Tuesday 03 May', StartTime: '09:00AM', EndTime: '05:00PM', Name: u'Billy Bones', Mobile: u'07XXX', 
Policy: u'Network Team', Level: 'Primary On Call Engineer', LevelNo: 1, StartDate: 'Friday 29 April', EndDate: 'Tuesday 03 May', StartTime: '05:00PM', EndTime: '03:30PM', Name: u'Jim Bob', Mobile: '07XXX'
]

Answer 1

我想这也应该管用

>>> sorted(a, key=lambda x: x['b'])
[{'a': 1, 'c': 2, 'b': 3}, {'a': 1, 'c': 2, 'b': 4}]
>>> 

PS：我使用虚拟数据是因为你的数据不是正确的python结构。你知道吗

在你的情况下

_OnCallData = sorted(OnCallData, key=lambda x: x.LevelNo)

Answer 2

这应该管用。你知道吗

def update(): #This defines the update procedure
    input_file=open("Scores.txt","r")      

    name=input("Enter name") #Uses variable to store name that is asked for
    highScore=input("Enter current high score")     
    newHighscore=input("Enter new high score")    

    data=input_file.read().splitlines()                    

    input_file.close    

    position=0 #Placing of the data at the start

    found=False

Answer 3

您需要导入itemgetter。首先将from operator import itemgetter添加到代码顶部。你知道吗