Django URL Regex未捕获到

Question

我想将一个整数解析为url，所以我像这样构建我的url（有3个url，因为可以没有参数，place或place和一个整数）

urlpatterns = [
    url(r'^map/$', geov.map_view, name = "map_view"),
    url(r'^map/(?P<search_place>[^\.]+)/$', geov.map_view, name = "map_view_accurate"),
    url(r'^map/(?P<search_place>[^\.]+)/(?P<digit>\d+)/$', geov.map_view),
]

所以在我看来：

def map_view(request, search_place = None, digit = 0):
    results = {}
    print(digit)
    if search_place is not None:
        query = Place_search.objects.filter(name_lower__icontains=search_place.lower()).order_by("-importance")
        results["query"] = query
    else:
        points = Place.objects.all()
        lon = points.count()

        results["points"]=points
        results["lon"] = lon

    return render_to_response("index.html", results)

但是digit总是0，查询变量没有得到任何元素。如果我只使用第二个url（例如：本地主机：8000/地图/马德里“工作正常）

Answer 1

第二个url的regexp通过第三个url捕获您想要捕获的内容，即使用斜杠和数字搜索位置，您应该将其更改为：

urlpatterns = [
    url(r'^map/$', geov.map_view, name = "map_view"),
    url(r'^map/(?P<search_place>[\w-]+)/$', geov.map_view, name = "map_view_accurate"),
    url(r'^map/(?P<search_place>[\w-]+)/(?P<digit>\d+)/$', geov.map_view),
]