如何在文本文件中找到最小的数字（Python2.5）

Question

到目前为止，我的代码在文本文件中找到了最大的数字，但没有找到最小的数字，当它运行时，最小的数字仍然是0，最大的是9997。

    integers = open('numbers.txt', 'r') # opens numbers.txt

largestInt = 0 # making variables to store the largest/smallest int
smallestInt = 0

# loop where we check every line for largest/smallest int
for line in integers:
    while largestInt <= line.strip():
        largestInt = line
    while smallestInt >= line.strip():
        smallestInt = line

# print results
print "Smallest = ", smallestInt
print "Largest = ", largestInt

numbers.txt看起来像：

6037
-2228
8712
-5951
9485
8354
1467
8089
559
9439
-4274
9278
-813
1156
-7528
1843
-9329
574

等等。

这里怎么了？如果我做错了什么，或者逻辑不正确，请纠正我。

EDIT

我要感谢@Martijn Pieters和@Gexos解释我做错了什么。我明白为什么我的代码现在工作了！

最终代码：

integers = open('numbers.txt', 'r') # opens numbers.txt

largestInt = 0 # making variables to store the largest/smallest int
smallestInt = 0

# loop where we check every line for largest/smallest int
for line in integers:
    if largestInt <= int(line.strip()): # converted a string into an int
        largestInt = int(line.strip()) # made that int into largestInt
    if smallestInt >= int(line.strip()): # converted a string into an int
        smallestInt = int(line.strip()) # made that int into smallestInt

integers.close() # closes the file

# print results
print "Smallest = ", smallestInt
print "Largest = ", largestInt

结果

Smallest =  -9993
Largest =  9997

Answer 1

正如其他人所说，您需要先将行转换为整数。此外，如果最小值大于零，脚本将不会输出正确的最小值。要解决此问题，请将最大值和最小值都设置为文件中的第一个条目。然后检查所有其他数字，看看它们是否比当前数字大/小。

with open('numbers.txt', 'r') as data_file:
    num = int(next(data_file))
    min_num, max_num = num, num
    for line in data_file:
        num = int(line)
        if num > max_num:
            max_num = num
        elif num < min_num:
            min_num = num

print 'Smallest number: {}'.format(min_num)
print 'Largest number: {}'.format(max_num)

这也可以通过列表理解来解决：

nums = [int(line) for line in open('numbers.txt', 'r')]
min_num, max_num = min(nums), max(nums)