python中嵌套树字典的公共祖先函数

Question

我正在尝试创建一个名为“common_祖先（）”的函数，它接受两个输入：第一个是字符串分类单元名称的列表，第二个是系统发生树字典。它应该返回一个字符串，给出分类单元的名称，这个分类单元是所有 输入列表中的物种。已经创建了一个名为“list_祖先”的单独函数，它给了我列表中元素的一般祖先。还有，有一本我正在用的词典。在

    tax_dict = { 
'Pan troglodytes': 'Hominoidea',       'Pongo abelii': 'Hominoidea', 
'Hominoidea': 'Simiiformes',           'Simiiformes': 'Haplorrhini', 
'Tarsius tarsier': 'Tarsiiformes',     'Haplorrhini': 'Primates',
'Tarsiiformes': 'Haplorrhini',         'Loris tardigradus':'Lorisidae',
'Lorisidae': 'Strepsirrhini',          'Strepsirrhini': 'Primates',
'Allocebus trichotis': 'Lemuriformes', 'Lemuriformes': 'Strepsirrhini',
'Galago alleni': 'Lorisiformes',       'Lorisiformes': 'Strepsirrhini',
'Galago moholi': 'Lorisiformes'
} 

def halfroot(tree):
    taxon = random.choice(list(tree))
    result = [taxon]
    for i in range(0,len(tree)): 
        result.append(tree.get(taxon))
        taxon = tree.get(taxon)
    return result


def root(tree):
    rootlist = halfroot(tree)
    rootlist2 = rootlist[::-1]
    newlist = []
    for e in range(0,len(rootlist)):
        if rootlist2[e] != None:
        newlist.append(rootlist2[e])
    return newlist[0]


def list_ancestors(taxon, tree):
    result = [taxon]
    while taxon != root(tree):
        result.append(tree.get(taxon))
        taxon = tree.get(taxon)
    return result

def common_ancestors(inputlist,tree)
    biglist1 = []
    for i in range(0,len(listname)):
        biglist1.append(list_ancestors(listname[i],tree))
        "continue so that I get three separate lists where i can cross reference all elements from the first list to every other list to find a common ancestor "

结果应该是

^{pr2}$

Answer 1

一种方法是收集每个物种的所有祖先，将他们放在一个集合中，然后得到一个交集，得到它们的共同点：

def common_ancestor(species_list, tree):
    result = None  # initiate a `None` result
    for species in species_list:  # loop through each species in the species_list
        ancestors = {species}  # initiate the ancestors set with the species itself
        while True:  # rinse & repeat until there are leaves in the ancestral tree
            try:
                species = tree[species]  # get the species' ancestor
                ancestors.add(species)  # store it in the ancestors set
            except KeyError:
                break
        # initiate the result or intersect it with ancestors from the previous species
        result = ancestors if result is None else result & ancestors
    # finally, return the ancestor if there is only one in the result, or None
    return result.pop() if result and len(result) == 1 else None

print(common_ancestor(["Hominoidea", "Pan troglodytes", "Lorisiformes"], tax_dict))
# Primates

您也可以将此函数的“中间”部分用于list_ancestors()-无需通过查找树的根来使其复杂化：

^{pr2}$

当然，两者都依赖于一个有效的祖先树字典——如果一些祖先在他们自己身上递归，或者如果链条上有一个断裂的话，那就不起作用了。另外，如果你要做很多这样的操作，把你的平面字典变成一个合适的树可能是值得的。在