擅长:python、mysql、java
<p>只是使用regex的另一种解决方法:</p>
<pre><code>#!/usr/bin/python
import re
def password_strength(p):
score = 0
if re.search('\d+',p):
score = score + 1
if re.search('[a-z]',p) and re.search('[A-Z]',p):
score = score + 1
if re.search('[$#@!]', p):
score = score + 1
return score
print password_strength('Jac@kpasswor01')
</code></pre>