好吧,所以我一直有一个问题,使一个变量的优先级与长度无关。我希望优秀学分被优先考虑,因为它是NCEA中价值最高的学分,然后我希望它优先考虑成绩,然后达到,直到它选出最好的80学分
到目前为止,我只看到了关于使用max()的示例,这不是我需要的
#Ncea Calculator
EXCELLENCE_THRESHOLD = 50
MERIT_THRESHOLD = 50
user_input_achieved = input("How many NCEA achieved credits do you have: ")
total_achieved_credits = int(user_input_achieved)
user_input_merit = input("How many NCEA merit credits do you have: ")
total_merit_credits = int(user_input_merit)
user_input_excellence = input("How many NCEA excellence credits do you have: ")
total_excellence_credits = int(user_input_excellence)
excellence_endorsement_applies = False
if total_excellence_credits >= EXCELLENCE_THRESHOLD:
excellence_endorsement_applies = True
merit_endorsement_applies = False
if total_merit_credits + total_excellence_credits >= MERIT_THRESHOLD:
merit_endorsement_applies = True
print('You have a total of', total_achieved_credits + total_merit_credits + total_excellence_credits ,'NCEA credits')
if excellence_endorsement_applies == True:
print("You also got an overall excellence endorsement, well done!")
if merit_endorsement_applies == True and excellence_endorsement_applies == False:
print("You got an overall merit endorsement, well done but there's still room for improvement!")
total_credits_this_year = total_achieved_credits + total_merit_credits + total_excellence_credits
if total_credits_this_year >= int(80):
print("You passed Ncea Level 1!")
if total_credits_this_year < int(79):
print("You failed Ncea Level 1, come on man!")
rank_score_achieved = int(user_input_achieved) * int(2)
rank_score_merit = int(user_input_merit) * int(3)
rank_score_excellence = int(user_input_excellence) * int(4)
total_rank_score = rank_score_achieved + rank_score_merit + rank_score_excellence
print ('your total rank score is', total_rank_score)
因此,如果用户写道:
^{pr2}$然后我希望它选择最好的80,这样它将选择50个优秀,然后30个优点学分,然后计算排名得分。在
这很难理解,但我相信OP只是尝试使用
name
作为排序索引来汇总值,直到值达到80。传统上,您将把这些
name:value
对存储在字典中,而不是变量,例如:然后,您可以简单地在
^{pr2}$sorted()
字典上迭代,直到得到总数,例如:相关问题 更多 >
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