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<p>我有以下Python2.7代码:</p>
<pre><code>listOfLists = []
for l1_index, l1 in enumerate(L1):
list = []
for l2 in L2:
for l3_index,l3 in enumerate(L3):
if (L4[l2-1] == l3):
value = L5[l2-1] * l1[l3_index]
list.<a href="https://www.cnpython.com/list/append" class="inner-link">append</a>(value)
break
listOfLists.append(list)
</code></pre>
<p>L1、L2、L3、L4、L5列表为:</p>
<pre><code>L1 = [[0.60, 0.95, 0.38, 1.02, 0.29, 0.43], [0.40, 0.09, 0.87, 0.85, 0.70, 0.46], [0.67, 0.91, 0.66, 0.79, 0.86, 0.06], [0.59, 1.81, 0.05, 1.88, 0.20, 0.48], [0.64, 0.34, 0.37, 1.39, 0.56, 0.27], [0.56, 0.34, 0.68, 2.79, 0.18, 0.42], [0.42, 1.67, 0.04, 0.44, 0.25, 0.94], [0.32, 1.92, 0.95, 2.85, 0.95, 0.96], [0.50, 0.68, 0.84, 1.79, 0.35, 0.09], [0.34, 0.66, 0.85, 0.35, 0.38, 0.59], [0.50, 0.79, 0.45, 2.93, 0.50, 0.92], [0.11, 0.11, 0.93, 1.11, 0.81, 0.49]] # a list of 12 sublists
L2 = [3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
L3 = [480, 120, 35, 0, 520, 300]
L4 = [120, 120, 120, 0, 300, 35, 35, 520, 300, 480, 120, 480, 0, 35, 0, 0, 300]
L5 = [5.4, 2.83, 1.16, 6.9, 0.76, 2.15, 5.61, 3.12, 1.57, 0.08, 5.36, 0.2, 1.2, 1.4, 2.9, 2.1, 3.5]
</code></pre>
<p>这些只是例子;实际上,这些列表包含数十万个数字。解释器需要几十秒来计算三个嵌套的<code>for</code>循环。</p>
<p>是否有可能以某种方式加速此代码,例如使用<code>itertools</code>或任何其他模块/函数?</p>
<p>编辑:我不能使用非标准的Python2.7模块(numpy,scipy…)</p>