我一直在尝试做一个加密和解密系统,但我遇到了一个小错误。这是我的代码:
import sys
import pyperclip
def copy(data):
question = input("Copy to clipboard? ")
if question.lower() == 'yes' or question.lower() == 'y':
pyperclip.copy(data)
print("Encrypted message copied to clipboard.")
rerun()
elif question.lower() == 'no' or question.lower() == 'n':
rerun()
else:
print("You did not enter a valid input.")
copy(data)
def rerun():
ask = input("\nWould you like to run this program again? ")
if ask.lower() == "yes" or ask.lower() == "y":
print(" ")
run()
elif ask.lower() == 'no' or ask.lower() == 'n':
sys.exit("\nThank you!")
else:
print("You did not enter a valid input.")
rerun()
def encrypt(key, msg):
encrypted_message = []
for i, c in enumerate(msg):
key_c = ord(key[i % len(key)])
msg_c = ord(c)
encrypted_message.append(chr((msg_c + key_c) % 127))
return ''.join(encrypted_message)
def decrypt(key, encrypted):
msg = []
for i, c in enumerate(encrypted):
key_c = ord(key[i % len(key)])
enc_c = ord(c)
msg.append(chr((enc_c - key_c) % 127))
return ''.join(msg)
def run():
function_type = input("Would you like to encrypt or decrypt a message? ")
if function_type.lower() == "encrypt" or function_type.lower() == "e":
key = input("\nKey: ")
msg = input("Message: ")
data = encrypt(key, msg)
enc_message = "\nYour encrypted message is: " + data
print(enc_message)
copy(data)
elif function_type.lower() == "decrypt" or function_type.lower() == "d":
key = input("\nKey: ")
question = input("Paste encrypted message from clipboard? ")
if question.lower() == 'yes' or question.lower() == 'y':
encrypted = pyperclip.paste()
print("Message: " + encrypted)
elif question.lower() == 'no' or question.lower() == 'n':
encrypted = input("Message: ")
else:
print("You did not enter a valid input.")
run()
decrypted = decrypt(key, encrypted)
decrypted_message = "\nYour decrypted message is: " + decrypted
print(decrypted_message)
copy(decrypted)
else:
print("\nYou did not enter a valid input.\n")
run()
run()
它说局部变量“encrypted”可能在赋值之前被引用并突出显示
decrypted = decrypt(key, encrypted)
在run()函数下。
是因为我在其他函数中使用了“encrypted”变量吗?如果是这样,我该如何解决这个问题,并仍然保持我的程序的功能?
我对python比较陌生,所以如果您能解释一下您的答案,我将不胜感激。
在
run()
之前添加encrypted = None
如果执行
else
分支,则不定义encrypted
。IDE不知道您再次调用run()
。请记住,这可能会导致无限递归,因此您应该使用另一个控制流机制(尝试使用
while
循环,该循环在输入有效时中断)是由绒布生成的警告。
这是因为linter看到
encrypted
在两个if条件内被赋值以及
但是,如果这两个条件是互补的,那么棉绒就不能知道这两个条件是互补的。因此,考虑到没有一个条件为真的情况,变量
encrypted
将最终未初始化。若要消除此警告,只需在使用
None
值的任何if
条件之前初始化变量相关问题 更多 >
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