怎么了？Python RSA解密/

Question

decrypt_message1+=decrypt_message[i]

TypeError: can't concat bytes to int.

decrypt_message1和{}都是字节

if int(length)>=1:
    for i in range(int(length)+1):
        decrypt_message1=""
        if i<int(length)+1:
            decrypt_message1=decrypt_message1.encode()
            for i in range(50):
                decrypt_message1+=decrypt_message[i]
            try:
                decrypt = rsa.decrypt(decrypt_message1, privkey)
            except Exception as E:
                print(E)
            decrypt=decrypt.decode()
            text1.insert(END,decrypt)
        else:
            decrypt_message1=decrypt_message1.encode()
            for i in range(len(message)-int(length)*20):
                decrypt_message1+=decrypt_message[i]
            try:
                decrypt = rsa.decrypt(decrypt_message1, privkey)
            except Exception as E:
                print(E)
            decrypt=decrypt.decode()
            text1.insert(END,decrypt)

Answer 1

我认为可能是+=运算符引起了问题，因为它调用了__iadd__，而不是{}。在

尝试decrypt_message1 = decrypt_message1 + decrypt_message[i]

Answer 2

decrypt_message[i]是一个bytes对象。它是一个int：

>>> b"hello"[0]
104

更改：

^{pr2}$

收件人：

decrypt_message1=decrypt_message1.encode()
decrypt_message1 += decrypt_message[:50]

---

索引在bytes中的简单下标返回存储在该位置的整数值。 切片返回一个bytes对象。看看这两者之间的区别：

>>> b"hello"[0]
104

以及：

>>> b"hello"[:1]
b'h'