如何从Python中的输出中提取特定信息

Question

所以我有一个给出输出的代码，我需要做的是把逗号之间的信息拉出来，把它们赋给一个变量，这个变量在被调用时会动态变化。。。这是我的代码：

import re

data_directory = 'Z:/Blender_Roto/'
data_file = 'diving_board.shape4ae'
fullpath = data_directory + data_file


print("====init=====")

file = open(fullpath)
for line in file:
current_line = line

# massive room for optimized code here.

# this assumes the last element of the line containing the words
# "Units Per Second" is the number we are looking for.
# this is a non float number, generally.
if current_line.find("Units Per Second") != -1:
    fps = line_split = float(current_line.split()[-1])
    print("Frames Per Second:", fps)

# source dimensions
if current_line.find("Source Width") != -1:
    source_width = line_split = int(current_line.split()[-1])
    print("Source Width:", source_width)

if current_line.find("Source Height") != -1:
    source_height = line_split = int(current_line.split()[-1])
    print("Source Height:", source_height)

# aspect ratios
if current_line.find("Source Pixel Aspect Ratio") != -1:
    source_px_aspect = line_split = int(current_line.split()[-1])
    print("Source Pixel Aspect Ratio:", source_px_aspect)

if current_line.find("Comp Pixel Aspect Ratio") != -1:
    comp_aspect = line_split = int(current_line.split()[-1])
    print("Comp Pixel Aspect Ratio:", comp_aspect)


# assumption, ae file can contain multiple mocha shapes.
# without knowing the exact format i will limit the script
# to deal with one mocha shape being animated N frames.

# this gathers the shape details, and frame number but does not
# include error checking yet.
if current_line.find("XSpline") != -1:

    # record the frame number.

    frame = re.search("\s*(\d*)\s*XSpline", current_line)
    if frame.group(1) != None:
        frame = frame.group(1)
        print("frame:", frame)


    # pick part the part of the line that deals with geometry
    match = re.search("XSpline\((.+)\)\n", current_line)

    line_to_strip = match.group(1)
    points = re.findall('(\(.*?\))', line_to_strip)

    print(len(points))
    for point in points:
        print(point)
    print("="*40)

file.close()

这给了我一个输出：

^{2}$

例如，我需要的是，能够将（0.793803，0.136326，0，0.5，0）分配给（1x，1y，1z，1w，1s），（0.772345，0.642332，0，0.5，0）到（2x，2y，2z，2w，2s）等，这样无论什么数字填充这些位置，它们都会使用这个值。在

下面是我需要把这些数字放入的代码：

#-------------------------------------------------------------------------------
# Name:        Mocha Rotoscoping Via Blender
# Purpose:     Make rotoscoping more efficient
#
# Author:      Jeff Owens
#
# Created:     11/07/2011
# Copyright:   (c) jeff.owens 2011
# Licence:     Grasshorse
#-------------------------------------------------------------------------------
#!/usr/bin/env python

import sys
import os
import parser
sys.path.append('Z:\_protomotion\Prog\HelperScripts')
import GetDir
sys.path.append('Z:\_tutorials\01\tut01_001\prod\Blender_Test')
filename = 'diving_board.shape4ae'
infile = 'Z:\_tutorials\01\tut01_001\prod\Blender_Test'
import bpy
from mathutils import Vector

#below are taken from mocha export
x_width =2048
y_height = 778
z_depth = 0
frame = 20

def readText():
text_file = open('diving_board.shape4ae', 'r')
lines = text_file.readlines()
print (lines)
print (len.lines)
for line in lines:
    print (line)

##sets points final x,y,z value taken from mocha export for blender interface

point1x = (0.642706 * x_width)
point1y = (0.597615 * y_height)
point1z = (0 * z_depth) 

point2x = (0.770557 * x_width)
point2y = (0.647039 * y_height)
point2z = (0 * z_depth)

point3x = (0.794697 * x_width)
point3y = (0.0869024 * y_height)
point3z = (0 * z_depth)


point4x = (0.707973* x_width)
point4y = (0.0751348 * y_height)
point4z = (0 * z_depth)


w = 1 # weight
listOfVectors = [Vector((point1x,point1y,point1z)),Vector((point2x,point2y,point2z)),Vector((point3x,point3    y,point3z)),Vector((point4x,point4y,point4z)), Vector((point1x,point1y,point1z))]

def MakePolyLine(objname, curvename, cList):
curvedata = bpy.data.curves.new(name=curvename, type='CURVE')
curvedata.dimensions = '3D'

objectdata = bpy.data.objects.new(objname, curvedata)
objectdata.location = (0,0,0) #object origin
bpy.context.scene.objects.link(objectdata)

polyline = curvedata.splines.new('POLY')
polyline.points.add(len(cList)-1)
for num in range(len(cList)):
    x, y, z = cList[num]
    polyline.points[num].co = (x, y, z, w)

MakePolyLine("NameOfMyCurveObject", "NameOfMyCurve", listOfVectors)

所以在我有向量的地方，我希望能够放置（p.x，p.y，0.z，p.w，p.s），然后（p2.x，p2.y，p2.zp2.wp2.s）等，这样它就可以根据给定的数发生变化

任何帮助都会很好。。提前谢谢你！在

-杰夫

Answer 1

您可以创建点对象并按名称为其编制索引，而不是打印每个输出。例如：

>>> class Point:
...     def __init__(self, t):
...         (self.x,self.y,self.z,self.w,self.s) = t
... 
>>> p = Point( (3,4,5,3,1) )
>>> p.w
3

可以将这些点对象放置在阵列中，然后通过

^{pr2}$

附录

如果重要的是从数组中提取点，而是使用实际的变量名，那么可以执行以下操作，其中points是元组的数组：

(p0x,p0y,p0z,p0w,p0s) = points[0]
(p1x,p1y,p1z,p1w,p1s) = points[1]
(p2x,p2y,p2z,p2w,p2s) = points[2]
...

等等。在

但是，请考虑一下这是否是一个合适的方法。有一个点类可以让你有任何数量的点。有了定义的变量名，就可以动态地创建无限数量的这些东西，但几乎总是一个坏主意。这里有一个关于这样做的警告：http://mail.python.org/pipermail/tutor/2005-January/035232.html。在

当你有一个点对象数组，你做你想做的更好！例如，您可以执行以下操作：

myPoints[i].y = 12

从而改变第i个点的y坐标。当您修复了变量名之后，这几乎是不可能的。希望有帮助！（希望我能理解你的澄清！如果没有请告诉我……）