如何在python中将unicode字符串转换为普通文本

Question

假设我有一个Unicode字符串（不是真正的Unicode，而是看起来像Unicode的字符串）。我想得到它的utf-8变种。我怎么用Python呢？ 例如，如果我有如下字符串：

title = "\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"

我怎样才能得到它的utf-8变体（格鲁吉亚符号）：

ისრაელი == იერუსალიმი

简单地说，我希望代码如下：

title = "\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"
utfTitle = title.TurnToUTF()
print(utfTitle)

我希望这段代码有输出：

ისრაელი == იერუსალიმი

Answer 1

您可以使用unicode-escape编解码器来消除重复的反斜杠，并有效地使用字符串。

假设title是一个str，则在解码回unicode（str）之前，需要先对字符串进行编码。

>>> t = title.encode('utf-8').decode('unicode-escape')
>>> t
'ისრაელი == იერუსალიმი'

如果title是bytes实例，则可以直接解码：

>>> t = title.decode('unicode-escape')
>>> t
'ისრაელი == იერუსალიმი'

Answer 2

给，你走。只需使用decode方法并应用unicode_escape

对于Python 2.x

title = "\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"
utfTitle = title.decode('unicode_escape')
print(utfTitle)

#output :ისრაელი == იერუსალიმი

对于python 3.x

title = "\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"
print(title.encode('ascii').decode('unicode-escape'))

Answer 3

假设unicode是str类型，并使用decode和unicode转义进行转换 方法

title="\\u10d8\\u10e1\\u10e0\\u10d0\\u10d4\\u10da\\u10d8 == \\u10d8\\u10d4\\u10e0\\u10e3\\u10e1\\u10d0\\u10da\\u10d8\\u10db\\u10d8"

res1 = title.encode('utf-8')

res2 = res1.decode('unicode-escape')

print(res2)