Python如何忽略或修复“索引器错误：列表索引超出范围”？

Question

所以这个结果一次可以得到少于10个答案。我很难弄清楚，如果“过负荷1”小于10，该如何忽略。例如，如果只有8个结果，我希望它显示8个结果，而忽略最后两个不存在的结果。在

    try:
        for i in range(10):
            (runo[i])
    except:
        pass

    overbought1 = ("Top 10 overbought today: $" + runo[0] + " $" + runo[1] + " $" + runo[2] + " $" + runo[3] + " $" +runo[4] + " $" + runo[5] + " $" + runo[6] + " $" + runo[7]+ " $" + runo[8]+ " $" + runo[9])

    await client.say(overbought1)

Answer 1

虽然整个示例没有什么意义，但以下是避免IndexError的方法之一：

for i in range(min(10, len(runo))): # loop at most to the minimum
                                    # between ten and len(runo)
    (runo[i]) # <  this does nothing here!

另一种方式：

^{pr2}$

现在，如果要修复overbought1字符串，请执行以下操作：

overbought1 = "Top 10 overbought today: $" + " $".join(runo[:10])

甚至：

overbought1 = ("Top %d overbought today: $" % len(runo)) + " $".join(runo[:10])