这是所需的输出。包含两行的CSV文件:
1639, 06/05/17, 08,09,16,26,37,50
1639, 06/05/17, 13,28,32,33,37,38
今天,我只有这个,但是使用VBA Excel代码来清理/组织数据:
^{pr2}$在第一行'1639,06/05/17'来自Resultado <span>Concurso 1639 (06/05/2017)</span>
,而'08,09,16,26,37,50'来自下面提供的标记:
在第二行,我们可以从第1行复制“1639,06/05/17”,而“13,28,32,33,37,38”则来自另一个标记:
<ul class="numbers dupla-sena">
<h6>2º sorteio</h6>
<li>13</li><li>28</li><li>32</li><li>33</li><li>37</li><li>38</li>
</ul>
以下是我的代码:
import requests
from bs4 import BeautifulSoup as soup
url = 'http://loterias.caixa.gov.br/wps/portal/loterias/landing/duplasena/'
r = requests.get(url)
ltr = soup(r.text, "xml")
ltr.findAll("div",{"class":"content-section section-text with-box no-margin-bottom"})
filename = "ds_1640.csv"
f=open(filename,"w")
使用下面的命令,我想我可以得到所有我想要的,但我不知道如何提取我需要的数据:
ltr.findAll("div",{"class":"content-section section-text with-box no-margin-bottom"})
所以,我尝试了另一种方法来捕捉“1ºsortio da dupla sena”中的值
print('-----------------dupla-sena 1º sorteio-----------------------------')
d1 = ltr.findAll("ul",{"class":"numbers dupla-sena"})[0].text.strip()
print(ltr.findAll("ul",{"class":"numbers dupla-sena"})[0].text.strip())
输出1
1º sorteio
080916263750
分开两位数
d1 = '0'+ d1 if len(d1)%2 else d1
gi = [iter(d1)]*2
r = [''.join(dz1) for dz1 in zip(*gi)]
d3=",".join(r)
结果呢
08,09,16,26,37,50
第二次提取也是如此
print('-----------------dupla-sena 2º sorteio-----------------------------')
dd1 = ltr.findAll("ul",{"class":"numbers dupla-sena"})[1].text.strip()
print(ltr.findAll("ul",{"class":"numbers dupla-sena"})[1].text.strip())
输出2
2º sorteio
132832333738
分开两位数
dd1 = '0'+ dd1 if len(dd1)%2 else dd1
gi = [iter(dd1)]*2
r1 = [''.join(ddz1) for ddz1 in zip(*gi)]
dd3=",".join(r1)
然后我们有了
13,28,32,33,37,38
将数据保存到csv文件
f.write(d3 + ',' + dd3 +'\n')
f.close()
输出:当前目录中的csv文件:
01,º ,so,rt,ei,o
,08,09,16,26,37,50,02,º ,so,rt,ei,o
,13,28,32,33,37,38
我可以使用上面的方法/输出,但是我必须使用VBA excel来处理这些混乱的数据,但是我尽量避免使用VBA代码。实际上,我对学习Python更感兴趣,并且越来越多地使用这个强大的工具。 通过这个解决方案,我只实现了我想要的一部分,那就是:
^{pr2}$但是,正如我们所知,期望的输出是:
1639, 06/05/17, 08,09,16,26,37,50
1639, 06/05/17, 13,28,32,33,37,38
我在macosxyosemite(10.10.5)中使用python3.6.1(v3.6.1:),Jupyter笔记本电脑。在
我怎么才能做到呢?我不知道如何提取“1639,06/05/17”并将其放入csv文件,有没有更好的方法来提取这六个数字(08,09,16,26,37,50和13,28,32,33,37,38),并且不使用下面的代码,也不使用vba?在
要分开两位数字:
d1 = '0'+ d1 if len(d1)%2 else d1
gi = [iter(d1)]*2
r = [''.join(dz1) for dz1 in zip(*gi)]
import requests
from bs4 import BeautifulSoup
import re
import csv
url = 'http://loterias.caixa.gov.br/wps/portal/loterias/landing/duplasena/'
r = requests.get(url)
soup = BeautifulSoup(r.text, "lxml") ## "lxml" to avoid the warning
pat = re.compile(r'(?i)(?<=concurso)\s*(?P<concurso>\d+)\s*\((?P<data>.+?)(?=\))')
concurso_e_data = soup.find(id='resultados').h2.span.text
match = pat.search(concurso_e_data)
# first I would do the above part differently seeing as how you want the end data to look
if match:
concurso, data = match.groups()
nums = soup.find_all("ul", {"class": "numbers dupla-sena"})
num_headers = (','.join(['numero%d']*6) % tuple(range(1,7))).split(',')
# unpack numheaders into field names
field_names = ['sena', 'data', *num_headers]
# above gives you this
# field_names = [
# 'sena', ## I've changed "seria"for "sena"
# 'data',
# 'numero1',
# 'numero2',
# 'numero3',
# 'numero4',
# 'numero5',
# 'numero6',
# ]
rows = []
# then add the numbers
# nums is all the `ul` list elements contains the drawing numbers
for group in nums:
# start each row with the shared concurso, data elements
row = [concurso, data]
# for each `ul` get all the `li` elements containing the individual number
for num in group.findAll('li'):
# add each number
row.append(int(num.text))
# get [('sena', '1234'), ('data', '12/13'2017'),...]
row_title_value_pairs = zip(field_names, row)
# turn into dict {'sena': '1234', 'data': '12/13/2017', ...}
row_dict = dict(row_title_value_pairs)
rows.append(row_dict)
# so now rows looks like: [{
# 'sena': '1234',
# 'data': '12/13/2017',
# 'numero1': 1,
# 'numero2': 2,
# 'numero3': 3,
# 'numero4': 4,
# 'numero5': 5,
# 'numero6': 6
# }, ...]
with open('file_v5.csv', 'w', encoding='utf-8') as csvfile:
csv_writer = csv.DictWriter(
csvfile,
fieldnames=field_names,
dialect='excel',
extrasaction='ignore', # drop extra fields if not in field_names not necessary but just in case
quoting=csv.QUOTE_NONNUMERIC # quote anything thats not a number, again just in case
)
csv_writer.writeheader()
for row in rows:
csv_writer.writerow(row_dict)
输出
^{pr21}$import requests
from bs4 import BeautifulSoup
import re
import csv
url = 'http://loterias.caixa.gov.br/wps/portal/loterias/landing/duplasena/'
r = requests.get(url)
soup = BeautifulSoup(r.text, "lxml") ## "lxml" to avoid the warning
pat = re.compile(r'(?i)(?<=concurso)\s*(?P<concurso>\d+)\s*\((?P<data>.+?)(?=\))')
concurso_e_data = soup.find(id='resultados').h2.span.text
match = pat.search(concurso_e_data)
# everything should be indented under this block since
# if there is no match then none of the below code should run
if match:
concurso, data = match.groups()
nums = soup.find_all("ul", {"class": "numbers dupla-sena"})
num_headers = (','.join(['numero%d']*6) % tuple(range(1,7))).split(',')
field_names = ['sena', 'data', *num_headers]
# PROBLEM 1
# all this should be indented into the `if match:` block above
# none of this should run if there is no match
# you cannot build the rows without the match for sena and data
# Let's add some print statements to see whats going on
rows = []
for group in nums:
# here each group is a full `sena` row from the site
print('Pulling sena: ', group.text)
row = [concurso, data]
print('Adding concurso + data to row: ', row)
for num in group.findAll('li'):
row.append(int(num.text))
print('Adding {} to row.'.format(num))
print('Row complete: ', row)
row_title_value_pairs = zip(field_names, row)
print('Transform row to header, value pairs: ', row_title_value_pairs)
row_dict = dict(row_title_value_pairs)
print('Row dictionary: ', row_dict)
rows.append(row_dict)
print('Rows: ', rows)
# PROBLEM 2
# It would seem that you've confused this section when switching
# out the original list comprehension with the more explicit
# for loop in building the rows.
# The below block should be indented to this level.
# Still under the `if match:`, but out of the the
# `for group in nums:` above
# the below block loops over rows, but you are still building
# the rows in the for loop
# you are effectively double looping over the values in `row`
with open('ds_v4_copy5.csv', 'w', encoding='utf-8') as csvfile:
csv_writer = csv.DictWriter(
csvfile,
fieldnames=field_names,
dialect='excel',
extrasaction='ignore', # drop extra fields if not in field_names not necessary but just in case
quoting=csv.QUOTE_NONNUMERIC # quote anything thats not a number, again just in case
)
csv_writer.writeheader()
# this is where you are looping extra because this block is in the `for` loop mentioned in my above notes
#for row in rows: ### I tried here to avoid the looping extra
#print('Adding row to CSV: ', row)
csv_writer.writerow(row_dict)
我想我是按照你的指示做的。但到目前为止:
"sena","data","numero1","numero2","numero3","numero4","numero5","numero6"
"1643","16/05/2017",3,4,9,19,21,26 #which is "1º sorteio"
仍然缺少“2ºsorteio”。我知道我做错了什么,因为“1ºsorteio”和“2ºsorteio”都在:
print(rows[0]) --> {'sena': '1643', 'data': '16/05/2017', 'numero1': 1, 'numero2': 21, 'numero3': 22, 'numero4': 43, 'numero5': 47, 'numero6': 50}
print(rows[1]) --> {'sena': '1643', 'data': '16/05/2017', 'numero1': 3, 'numero2': 4, 'numero3': 9, 'numero4': 19, 'numero5': 21, 'numero6': 26}
但是,当我试图在csv中存储“行”的内容时(只有行[0]出现在“行”dict中,我正试图找出如何包括丢失的行。也许我错了,但我认为“1ºsorteio”和“2ºsorteio”都应该包含在row甪dict中,但是代码并不能确认它(这只是猜测):
print(row_dict)
{'sena': '1643', 'data': '16/05/2017', 'numero1': 3, 'numero2': 4, 'numero3': 9, 'numero4': 19, 'numero5': 21, 'numero6': 26}
我看不出我做错了什么。我知道回答这个问题要花很多时间,但在这个过程中我和你一起学到了很多东西。并且已经使用了我和您一起学习的几个工具(re,concepts,dict,zip)。在
(代表运营商发布)。在
在你的帮助下,我们到了!输出我需要的方式!我已将输出更改为:
因此,根据他们对Excel中“,”和“;”的关注,我决定将}在Excel中打开列,没有任何问题。在
^{pr2}$","
改为{免责声明:我对靓汤不太熟悉,我通常用lxml,也就是说。。。在
虽然这是您要求的格式,但在数字组中使用comas(列分隔符)不是个坏主意吗。您应该用另一个字符分隔,或者用空格分隔数字。在
更新1:
在评论区写不是最好的方法,所以。。。假设您真正想要的格式是8行,如下所示}是字符串,数字是
^{pr2}$(seria, data, num1, num2, ... num6)
,其中seria
和{int
s:这部分有点混乱:
所以让我换一种方式写:
更新2:
我希望您从中学习到的一件事是在学习时使用
print
语句,以便您能够理解代码的作用。我不做更正,但我会指出它们,并在每个发生重大变化的位置添加print
语句。。。在运行这个,看看打印语句显示了什么。但也要读一下注释,因为如果sena,data不匹配,会导致错误。在
提示:进行缩进,然后在末尾的
if match:
块下添加else: print('No sena, data match!')
。。。但先运行这个,然后检查打印的内容。在相关问题 更多 >
编程相关推荐