在不同的行中打印每个列表元素，在每个元素前面重复一个字符串Python

Question

我想在列表的每个元素前面打印一个字符串，然后在新行中打印：

示例：

    test = ["aaa", "bee", "cee"]
    print("hello, %s" % "\n".join(storageVolume))

我从中得到的是：

^{pr2}$

我想要的是：

    hello, aaa
    hello, bee
    hello, cee

感谢任何帮助。在

Answer 1

In [10]: test = ["aaa", "bee", "cee"]

In [11]: print "\n".join("hello, "+x for x in test)
hello, aaa
hello, bee
hello, cee

或者：

^{pr2}$

Answer 2

for x in test:
    print "Hello, {0}".format(x) 

Answer 3

In [51]: test = ["aaa", "bee", "cee"]

In [52]: for elem in test:
   ....:     print "hello,", elem
   ....:
hello, aaa
hello, bee
hello, cee