你能把c++快速json对象转换成Python json对象吗?

2024-03-29 05:19:10 发布

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我正在构建一个C++项目,它连接到一个客户拥有的Python代码库并向Jython代码发送JSON对象。由于python代码库是客户所有的,因此我无法修改python代码库以接收json字符串。我正在使用PythonC/API作为接口。

我构建了一个小python文件,使用python的json库将json字符串转换为json对象。我更愿意用Rabijson在C++侧写JSON对象。我能从C++快速JSON构建Python JSON对象并让它在Python的JSON库中读取而不将对象转换为字符串吗?如果可能,哪个函数将是将json文档转换为Python对象的正确函数?

C++:
PyObject* packJsonDict;
PyObject* customerDict;

int PYCPP::getJsonToInterface()
{
    std::string json= "{\"pet\": \"dog\", \"count\": 5}";
    PyObject* JsonObject = m_pImpl->pack_JsonString(json);

    std::string function_string = "read_json";
    PyObject* args = PyTuple_Pack(1, JsonObject);

    //trying packing just the json string
    PyObject* runnableFunction = PyDict_GetItemString(customerDict,     (char*)function_string);
    PyObject* result = PyObject_CallObject(runnableFunction, args);
}

PyObject* PYCPP::pack_JsonString(std::string json_string)
{
    std::string function_string = "convert_jsonString_to_jsonObject";
    PyObject* args = PyTuple_Pack(1, PyString_FromString((char*)    json_string.c_str()) );

    //trying packing just the json string
    PyObject* runnableFunction = PyDict_GetItemString(packJsonDict,     (char*)function_string);
    PyObject* result = PyObject_CallObject(runnableFunction, args);

    if(result == nullptr)
    {
        std::cout << "result was null!\n";
    }
    return result;
}

Python:
import json

def convert_jsonString_to_jsonObject(jsonString):

    print "converting:", jsonString

    return json.loads(jsonString)

Tags: 对象字符串代码jsonstring客户argsfunction