Python按两个值对列表排序

Question

我试着把这个单子按名字倒序排序。然后，在第一组结果（其中flag=“ZAR”）之后，我想按时间（而不是反向）对其余元素进行排序：

import operator
list = [
    {"flag":"ZAR", "time":"17:45"},
    {"flag":"AUS", "time":"17:30"},
    {"flag":"AUS", "time":"17:15"},
    {"flag":"USA", "time":"17:00"},
    {"flag":"GBP", "time":"16:55"},
    {"flag":"ZAR", "time":"16:45"},
    {"flag":"USA", "time":"16:35"},
    {"flag":"GBP", "time":"16:25"},
    {"flag":"ZAR", "time":"16:15"},
]

list.sort(key=operator.itemgetter("time"))
list.sort(key=operator.itemgetter("flag"),reverse=True)


print list

[{'flag': 'ZAR', 'time': '16:15'}, {'flag': 'ZAR', 'time': '16:45'}, {'flag': 'ZAR', 'time': '17:45'}, {'flag': 'USA', 'time': '16:35'}, {'flag': 'USA', 'time': '17:00'}, {'flag': 'GBP', 'time': '16:25'}, {'flag': 'GBP', 'time': '16:55'}, {'flag': 'AUS', 'time': '17:15'}, {'flag': 'AUS', 'time': '17:30'}]

正如您所看到的，flag sort是正确的，但是其他元素只在经过排序的国家中按时间排序。在

我想要的是总是先有ZAR，然后不管旗名是什么，只在乎时间。所以它应该给出这个结果：

^{pr2}$

怎么做呢？在

Answer 1

将您的代码修改为：

import operator
data = [
    {"flag":"ZAR", "time":"17:45"},
    {"flag":"AUS", "time":"17:15"},
    {"flag":"USA", "time":"17:00"},
    {"flag":"GBP", "time":"16:55"},
    {"flag":"ZAR", "time":"16:45"},
    {"flag":"USA", "time":"16:35"},
    {"flag":"GBP", "time":"16:25"},
    {"flag":"ZAR", "time":"16:15"},
]

data.sort(key=operator.itemgetter("time"))
data.sort(key=lambda L: L['flag'] == 'ZAR', reverse=True)

# [{'flag': 'ZAR', 'time': '16:15'}, {'flag': 'ZAR', 'time': '16:45'}, {'flag': 'ZAR', 'time': '17:45'}, {'flag': 'GBP', 'time': '16:25'}, {'flag': 'USA', 'time': '16:35'}, {'flag': 'GBP', 'time': '16:55'}, {'flag': 'USA', 'time': '17:00'}, {'flag': 'AUS', 'time': '17:15'}, {'flag': 'AUS', 'time': '17:30'}]