与ipython-shell-escap结合的Tuple解包

Question

如何在ipython中解压shell escape的输出？在

实例（作品）：

In [1]: !locate .hgrc
/home/wim/.hgrc
/usr/share/doc/mercurial-common/examples/sample.hgrc

In [2]: hgrcs = !locate .hgrc

In [3]: hgrcs[0]
Out[3]: '/home/wim/.hgrc'

但这行不通：

^{pr2}$

同样不起作用：

In [13]: x = !locate .hgrc | head -1

In [14]: x
Out[14]: ['/home/wim/.hgrc']

In [15]: x, = !locate .hgrc | head -1
  File "<ipython-input-15-524d2c9ab16f>", line 1
    x, = !locate .hgrc | head -1
         ^
SyntaxError: invalid syntax

python3.3.2+上的IPython 0.13.2。在

Answer 1

这个问题在我提交了一个issue后不久就解决了。在

https://github.com/ipython/ipython/pull/5321

Answer 2

恶心，但对于这个特殊的案例：

hgrc0, _ = !locate .hgrc | head -1 | printf '%s\n_' $(cat)