python中如何使用yield函数

Question

SyntaxError:“yield”外部函数

>>> for x in range(10):
...     yield x*x
... 
  File "<stdin>", line 2
SyntaxError: 'yield' outside function

我该怎么办？当我尝试使用简单的循环屈服。

Answer 1

编辑

你在评论中引用了scala，所以我认为你可能是在理解列表之后：

>>> squares = [i*i for i in range(10)]
>>> squares
[0, 1, 4, 9, 16, 25, 36, 49, 64, 81]

也可以使用生成器表达式：

>>> squares = (i*i for i in range(10))
>>> squares
<generator object <genexpr> at 0x7f5299e04690>
>>> list(squares)
[0, 1, 4, 9, 16, 25, 36, 49, 64, 81]

---

您需要从函数中调用yield。这使函数成为生成器函数。然后，您可以对函数生成的连续值进行迭代，例如：

def squares(N):
    for i in range(N):
        yield i*i

>>> squares(10)
<generator object squares at 0x7f5299e04500>
>>> for n in squares(10):
...    print(n)
0
1
4
9
16
25
36
49
64
81

>>> list(squares(100))
[0, 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484, 529, 576, 625, 676, 729, 784, 841, 900, 961, 1024, 1089, 1156, 1225, 1296, 1369, 1444, 1521, 1600, 1681, 1764, 1849, 1936, 2025, 2116, 2209, 2304, 2401, 2500, 2601, 2704, 2809, 2916, 3025, 3136, 3249, 3364, 3481, 3600, 3721, 3844, 3969, 4096, 4225, 4356, 4489, 4624, 4761, 4900, 5041, 5184, 5329, 5476, 5625, 5776, 5929, 6084, 6241, 6400, 6561, 6724, 6889, 7056, 7225, 7396, 7569, 7744, 7921, 8100, 8281, 8464, 8649, 8836, 9025, 9216, 9409, 9604, 9801]