我有一些数据需要分解成可管理的块。用下面的数据,我需要计算x在第11列中出现的次数(第7列为1)以及第11列中出现的次数。我需要把它们放到csv的第一行。之后,我需要计算相同的东西,但第11列是以下括号:
0
“>;0但是<;0.05”
“>;0.05但<;0.10”
“>;0.1但<;0.15。。。一直到1.00“
理想情况下,所有这些都应该附加到同一个文件中新建.csvi、 e.不是主数据csv
一些符合上述描述的原始数据示例(请注意,许多括号将不包含任何数据。在这种情况下,它们需要返回0,0:
01/01/2002,Data,class1,4,11yo+,4,1,George Smith,0,0,x
01/01/2002,Data,class1,4,11yo+,4,2,Ted James,0,0,x
01/01/2002,Data,class1,4,11yo+,4,3,Emma Lilly,0,0,x
01/01/2002,Data,class1,4,11yo+,4,5,George Smith,0,0,x
02/01/2002,Data,class2,4,10yo+,6,4,Tom Phillips,0,0,x
02/01/2002,Data,class2,4,10yo+,6,2,Tom Phillips,0,0,x
02/01/2002,Data,class2,4,10yo+,6,5,George Smith,1,2,0.5
02/01/2002,Data,class2,4,10yo+,6,3,Tom Phillips,0,0,x
02/01/2002,Data,class2,4,10yo+,6,1,Emma Lilly,0,1,0
02/01/2002,Data,class2,4,10yo+,6,6,George Smith,1,2,0.5
03/01/2002,Data,class3,4,10yo+,6,6,Ted James,0,1,0
03/01/2002,Data,class3,4,10yo+,6,3,Tom Phillips,0,3,0
03/01/2002,Data,class3,4,10yo+,6,2,George Smith,1,4,0.25
03/01/2002,Data,class3,4,10yo+,6,4,George Smith,1,4,0.25
03/01/2002,Data,class3,4,10yo+,6,1,George Smith,1,4,0.25
03/01/2002,Data,class3,4,10yo+,6,5,Tom Phillips,0,3,0
04/01/2002,Data,class4,2,10yo+,5,3,Emma Lilly,1,2,0.5
04/01/2002,Data,class4,2,10yo+,5,1,Ted James,0,2,0
04/01/2002,Data,class4,2,10yo+,5,2,George Smith,2,7,0.285714286
04/01/2002,Data,class4,2,10yo+,5,4,Emma Lilly,1,2,0.5
04/01/2002,Data,class4,2,10yo+,5,5,Tom Phillips,0,5,0
05/01/2002,Data,class5,4,11yo+,4,1,George Smith,2,8,0.25
05/01/2002,Data,class5,4,11yo+,4,2,Ted James,1,3,0.333333333
05/01/2002,Data,class5,4,11yo+,4,3,Emma Lilly,1,4,0.25
05/01/2002,Data,class5,4,11yo+,4,5,George Smith,2,8,0.25
06/01/2002,Data,class6,4,10yo+,6,4,Tom Phillips,0,6,0
06/01/2002,Data,class6,4,10yo+,6,2,Tom Phillips,0,6,0
06/01/2002,Data,class6,4,10yo+,6,5,George Smith,3,10,0.3
06/01/2002,Data,class6,4,10yo+,6,3,Tom Phillips,0,6,0
06/01/2002,Data,class6,4,10yo+,6,1,Emma Lilly,1,5,0.2
06/01/2002,Data,class6,4,10yo+,6,6,George Smith,3,10,0.3
07/01/2002,Data,class7,4,10yo+,6,6,Ted James,1,4,0.25
07/01/2002,Data,class7,4,10yo+,6,3,Tom Phillips,0,9,0
07/01/2002,Data,class7,4,10yo+,6,2,George Smith,3,12,0.25
07/01/2002,Data,class7,4,10yo+,6,4,George Smith,3,12,0.25
07/01/2002,Data,class7,4,10yo+,6,1,George Smith,3,12,0.25
07/01/2002,Data,class7,4,10yo+,6,5,Tom Phillips,0,9,0
08/01/2002,Data,class8,2,10yo+,5,3,Emma Lilly,2,6,0.333333333
08/01/2002,Data,class8,2,10yo+,5,1,Ted James,1,5,0.2
08/01/2002,Data,class8,2,10yo+,5,2,George Smith,4,15,0.266666667
08/01/2002,Data,class8,2,10yo+,5,4,Emma Lilly,2,6,0.333333333
08/01/2002,Data,class8,2,10yo+,5,5,Tom Phillips,0,11,0
09/01/2002,Data,class9,4,11yo+,4,1,George Smith,4,16,0.25
09/01/2002,Data,class9,4,11yo+,4,2,Ted James,2,6,0.333333333
09/01/2002,Data,class9,4,11yo+,4,3,Emma Lilly,2,8,0.25
09/01/2002,Data,class9,4,11yo+,4,5,George Smith,4,16,0.25
10/01/2002,Data,class10,4,10yo+,6,4,Tom Phillips,0,12,0
10/01/2002,Data,class10,4,10yo+,6,2,Tom Phillips,0,12,0
10/01/2002,Data,class10,4,10yo+,6,5,George Smith,5,18,0.277777778
10/01/2002,Data,class10,4,10yo+,6,3,Tom Phillips,0,12,0
10/01/2002,Data,class10,4,10yo+,6,1,Emma Lilly,2,9,0.222222222
10/01/2002,Data,class10,4,10yo+,6,6,George Smith,5,18,0.277777778
11/01/2002,Data,class11,4,10yo+,6,6,Ted James,2,7,0.285714286
11/01/2002,Data,class11,4,10yo+,6,3,Tom Phillips,0,15,0
11/01/2002,Data,class11,4,10yo+,6,2,George Smith,5,20,0.25
11/01/2002,Data,class11,4,10yo+,6,4,George Smith,5,20,0.25
11/01/2002,Data,class11,4,10yo+,6,1,George Smith,5,20,0.25
11/01/2002,Data,class11,4,10yo+,6,5,Tom Phillips,0,15,0
12/01/2002,Data,class12,2,10yo+,5,3,Emma Lilly,3,10,0.3
12/01/2002,Data,class12,2,10yo+,5,1,Ted James,2,8,0.25
12/01/2002,Data,class12,2,10yo+,5,2,George Smith,6,23,0.260869565
12/01/2002,Data,class12,2,10yo+,5,4,Emma Lilly,3,10,0.3
12/01/2002,Data,class12,2,10yo+,5,5,Tom Phillips,0,17,0
13/01/2002,Data,class13,4,11yo+,4,1,George Smith,6,24,0.25
13/01/2002,Data,class13,4,11yo+,4,2,Ted James,3,9,0.333333333
13/01/2002,Data,class13,4,11yo+,4,3,Emma Lilly,3,12,0.25
13/01/2002,Data,class13,4,11yo+,4,5,George Smith,6,24,0.25
14/01/2002,Data,class14,4,10yo+,6,4,Tom Phillips,0,18,0
14/01/2002,Data,class14,4,10yo+,6,2,Tom Phillips,0,18,0
14/01/2002,Data,class14,4,10yo+,6,5,George Smith,7,26,0.269230769
14/01/2002,Data,class14,4,10yo+,6,3,Tom Phillips,0,18,0
14/01/2002,Data,class14,4,10yo+,6,1,Emma Lilly,3,13,0.230769231
14/01/2002,Data,class14,4,10yo+,6,6,George Smith,7,26,0.269230769
15/01/2002,Data,class15,4,10yo+,6,6,Ted James,3,10,0.3
如果有人能帮我做到这一点,我将非常感激。如果这需要更多细节,请询问。在
最后一点需要注意的是,有问题的csv有800k行。在
编辑
当前,使用@user650654提供的代码,输出文件显示如下:
^{pr2}$如果有可能的话,我希望代码稍微改变一下,再放两个东西。希望这些不是很难做到。对输出文件的建议更改(逗号代表每一新行):
title row labeling the row (e.g. "x" or "0:0.05",Calculated avereage of values within each bracket e.g."0.02469",data1,data2
所以在现实中可能会是这样的:
x,n/a,data1,data2
0:0.05,0.02469,data1,data2
0.05:0.1,0.5469,data1,data2
....
....
Column1=行标签(原始问题中正在计数的数据范围,即从0到0.05 第2列=特定范围内数值的计算平均值。一、 e.如果 注意data1和data2是问题最初询问的两个值。 第1栏
非常感谢AEA
此解决方案使用
numpy.histogram
。见下文。在下面是添加两个新字段的解决方案:
这可能有用:
这给了我
^{pr2}$相关问题 更多 >
编程相关推荐