我想将请求url和请求体作为xml输入,并将输出作为响应xml代码。在
有没有这个的代码片段。在
虽然我有一个Java代码:
import java.net.*; // import java packages.
import java.io.*;
import java.net.URL;
public class POST {
public static void main(String[] args) {
try{
URL url = new URL(""); // Http request
URLConnection con = url.openConnection();
con.setDoInput(true);
con.setDoOutput(true);
con.setConnectTimeout( 20000 );
con.setReadTimeout( 20000 );
con.setUseCaches (false);
con.setDefaultUseCaches (false);
con.setRequestProperty ( "Content-Type", "application/xml" );
OutputStreamWriter writer = new OutputStreamWriter( con.getOutputStream());
writer.write("xml request body"); // xml request body
writer.flush();
writer.close();
InputStreamReader reader = new InputStreamReader( con.getInputStream() );
StringBuilder buf = new StringBuilder();
char[] cbuf = new char[ 2048 ];
int num;
while ( -1 != (num=reader.read( cbuf )))
{
buf.append( cbuf, 0, num );
}
String result = buf.toString();
System.err.println( "\nResponse from server after POST:\n" + result );
}
catch( Throwable t )
{
t.printStackTrace( System.out );
}
}
}
您可以这样做:
对于Python 3,可以执行以下操作:
^{pr2}$相关问题 更多 >
编程相关推荐