2024-05-13 02:43:22 发布
网友
如何使我的qmenu可检查?
from PyQt4 import QtGui app = QtGui.QApplication([]) menu = QtGui.QMenu() menu.addAction('50%') menu.addAction('100%') menu.addAction('200%') menu.addAction('400%') menu.show() app.exec_()
我建议在compact first解决方案中添加几行,以显示按钮的实际用途:
from PyQt4 import QtGui, QtCore def isChecked(): """ Prints selected menu labels. """ [print(action.text()) for action in menu.actions() if action.isChecked()] app = QtGui.QApplication([]) w = QtGui.QMainWindow() menu = QtGui.QMenu("menu", w) menu.addAction(QtGui.QAction('50%', menu, checkable=True)) menu.addAction(QtGui.QAction('100%', menu, checkable=True)) menu.addAction(QtGui.QAction('200%', menu, checkable=True)) menu.addAction(QtGui.QAction('400%', menu, checkable=True)) menu.triggered.connect(isChecked) w.menuBar().addMenu(menu) w.show() app.exec_()
像这样:
from PyQt4 import QtGui app = QtGui.QApplication([]) w = QtGui.QMainWindow() menu = QtGui.QMenu("menu", w) menu.addAction(QtGui.QAction('50%', menu, checkable=True)) menu.addAction(QtGui.QAction('100%', menu, checkable=True)) menu.addAction(QtGui.QAction('200%', menu, checkable=True)) menu.addAction(QtGui.QAction('300%', menu, checkable=True)) menu.addAction(QtGui.QAction('400%', menu, checkable=True)) w.menuBar().addMenu(menu) w.show() app.exec_()
或使用单选按钮:
from PyQt4 import QtGui app = QtGui.QApplication([]) w = QtGui.QMainWindow() menu = QtGui.QMenu("menu", w) ag = QtGui.QActionGroup(w, exclusive=True) a = ag.addAction(QtGui.QAction('50%', w, checkable=True)) menu.addAction(a) a = ag.addAction(QtGui.QAction('100%', w, checkable=True)) menu.addAction(a) a = ag.addAction(QtGui.QAction('200%', w, checkable=True)) menu.addAction(a) a = ag.addAction(QtGui.QAction('300%', w, checkable=True)) menu.addAction(a) a = ag.addAction(QtGui.QAction('400%', w, checkable=True)) menu.addAction(a) w.menuBar().addMenu(menu) w.show() app.exec_()
我建议在compact first解决方案中添加几行,以显示按钮的实际用途:
像这样:
或使用单选按钮:
相关问题 更多 >
编程相关推荐