在Django中填充URLFields的合法值的确切模式是什么？

Question

我需要一组字符串的精确定义，这些字符串被认为是models.URLField的合法URL。在

作为一个正规表达式或其他形式的解释，我可以验证任何形式的代码的正确性。在

Answer 1

查看源代码，似乎URLField是一个CharField，它将一个validators.URLValidator添加到字段的验证器列表中，并从django.core导入。在

来自site-packages/django/core/validators.py：

class URLValidator(RegexValidator):
    regex = re.compile(
        r'^https?://' # http:// or https://
        r'(?:(?:[A-Z0-9](?:[A-Z0-9-]{0,61}[A-Z0-9])?\.)+[A-Z]{2,6}\.?|' #domain...
        r'localhost|' #localhost...
        r'\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})' # ...or ip
        r'(?::\d+)?' # optional port
        r'(?:/?|[/?]\S+)$', re.IGNORECASE)

    def __init__(self, verify_exists=False, validator_user_agent=URL_VALIDATOR_USER_AGENT):
        super(URLValidator, self).__init__()
        self.verify_exists = verify_exists
        self.user_agent = validator_user_agent

    def __call__(self, value):
        try:
            super(URLValidator, self).__call__(value)
        except ValidationError, e:
            # Trivial case failed. Try for possible IDN domain
            if value:
                value = smart_unicode(value)
                scheme, netloc, path, query, fragment = urlparse.urlsplit(value)
                try:
                    netloc = netloc.encode('idna') # IDN -> ACE
                except UnicodeError: # invalid domain part
                    raise e
                url = urlparse.urlunsplit((scheme, netloc, path, query, fragment))
                super(URLValidator, self).__call__(url)
            else:
                raise
        else:
            url = value

        if self.verify_exists:
            import urllib2
            headers = {
                "Accept": "text/xml,application/xml,application/xhtml+xml,text/html;q=0.9,text/plain;q=0.8,image/png,*/*;q=0.5",
                "Accept-Language": "en-us,en;q=0.5",
                "Accept-Charset": "ISO-8859-1,utf-8;q=0.7,*;q=0.7",
                "Connection": "close",
                "User-Agent": self.user_agent,
            }
            try:
                req = urllib2.Request(url, None, headers)
                u = urllib2.urlopen(req)
            except ValueError:
                raise ValidationError(_(u'Enter a valid URL.'), code='invalid')
            except: # urllib2.URLError, httplib.InvalidURL, etc.
                raise ValidationError(_(u'This URL appears to be a broken link.'), code='invalid_link')

因此它尝试对regex进行验证，如果验证失败，它将使用Python的urlparse模块取消域名的IDN并重试。在