第一个帖子在这里。所以我尝试实现一个文明型的动作游戏。现在,我的牢房里有一个精灵。我可以单击它,然后如果我单击另一个网格,精灵就会移动到那里。我现在想要的是繁殖5-6个这样的精灵,然后做同样的事情。单击一个精灵,然后单击另一个栅格,这个特定的精灵就会移动到那里而不会影响其他精灵。我好像做不到。我可以在不同的网格上随机生成5-6个精灵,但是当我点击其中一个然后点击另一个网格时,所有其他精灵都消失了。下面是代码(不是我学习Pygame时最好的代码)。我知道我必须以某种方式只更新被点击的精灵,但我不知道怎么做。在
import pygame
import random
WIDTH = 900
HEIGHT = 700
FPS = 2
WHITE = (255, 255, 255)
BLACK = (0, 0, 0)
RED = (255, 0, 0)
GREEN = (0, 255, 0)
BLUE = (0, 0, 255)
TURN = "TeamOne"
def main():
# Pygame sprite Example
global x_lines
global y_lines
x_lines = [WIDTH-i*WIDTH/20 for i in range(20,0, -1)]
y_lines = [HEIGHT-j*HEIGHT/20 for j in range(20,0, -1)]
class TeamOne(pygame.sprite.Sprite):
# sprite for the Player
def __init__(self):
# this line is required to properly create the sprite
pygame.sprite.Sprite.__init__(self)
# create a plain rectangle for the sprite image
self.image = pygame.Surface((WIDTH / 20, HEIGHT / 20))
self.image.fill(GREEN)
# find the rectangle that encloses the image
self.rect = self.image.get_rect()
# center the sprite on the screen
self.rect.center = ((random.randint(1,19)*2+1)* WIDTH/ 40, (random.randint(1,19)*2+1)*HEIGHT/40)
def update(self, position):
# any code here will happen every time the game loop updates
(a, b) = position
for index, i in enumerate(x_lines):
if i > a:
self.rect.x = x_lines[index-1]
break
for index, j in enumerate(y_lines):
if j > b:
self.rect.y = y_lines[index-1]
break
# initialize pygame and create window
pygame.init()
screen = pygame.display.set_mode((WIDTH, HEIGHT))
pygame.display.set_caption("A Game")
clock = pygame.time.Clock()
clicked_sprites = pygame.sprite.Group()
teamone_sprites = pygame.sprite.Group()
for i in range(5):
mob1 = TeamOne()
teamone_sprites.add(mob1)
# Game loop
running = True
j=0
while running:
# keep loop running at the right speed
clock.tick(FPS)
# Process input (events)
for event in pygame.event.get():
# check for closing window
if event.type == pygame.QUIT:
running = False
elif event.type == pygame.MOUSEBUTTONDOWN and j == 0:
pos = pygame.mouse.get_pos()
for s in teamone_sprites:
if s.rect.collidepoint(pos):
#teamone_sprites.add(s)
clicked_sprites.add(s)
print (clicked_sprites)
j = 1
elif event.type == pygame.MOUSEBUTTONDOWN and j == 1:
new_pos = pygame.mouse.get_pos()
#teamone_sprites.update(new_pos)
clicked_sprites.update(new_pos)
j = 0
# Update
# Draw / render
## screen.fill(BLACK)
## draw_grid(screen)
##
## teamone_sprites.draw(screen)
##
##
##
## # *after* drawing everything, flip the display
## pygame.display.flip()
# Draw / render
screen.fill(BLACK)
draw_grid(screen)
teamone_sprites.draw(screen)
pygame.display.flip()
pygame.quit()
def draw_grid(screen):
for i in range(1, HEIGHT, int(HEIGHT/20)):
pygame.draw.line(screen, GREEN, (1,i) ,(WIDTH,i), 2)
for j in range(1, WIDTH, int(WIDTH/20)):
pygame.draw.line(screen, GREEN, (j,1) ,(j,HEIGHT), 2)
if __name__ == '__main__':
main()
给你的一些建议:
pygame.display.flip()
/pygame.display.update()
一次j
下面是一个简单的可运行的示例,我将其组合在一起(请参见注释以了解一些解释):
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