python3中LogonUserW中的访问冲突

Question

我正在为某人编写一个Python3脚本，它通过ctypes利用advapi dll及其LogonUserW函数。在

运行代码时

在函数中

dll_location = find_library("advapi32");

if (dll_location == None):
    raise FileNotFoundError

adv_dll = WinDLL(dll_location);

#gets the pointer to the function
logonUser = adv_dll.LogonUserW;
self.logonUser = logonUser

在登录（用户名、域、密码）功能中

^{pr2}$

它引起OSError: exception: access violation writing 0x0000000000000000

你知道是什么导致了这个错误吗？怎么解决？在

PS：是的，我知道我不是按照PEP8来寻找变量名的，我通常是一名java程序员。在

Answer 1

{{{1}根据{1}你应该调用{1}函数。在

下面是一个调用它的最小示例。但是，如果您需要调用多个这样的函数，您也可以考虑[GitHub]: Python for Windows (pywin32) Extensions，它是一个覆盖WINAPIs的Python包装器

代码.py：

import sys
import ctypes
from ctypes import wintypes


def main():
    advapi32_dll = ctypes.WinDLL("advapi32.dll")
    logon_user_func = advapi32_dll.LogonUserW
    logon_user_func.argtypes = [wintypes.LPCWSTR, wintypes.LPCWSTR, wintypes.LPCWSTR, wintypes.DWORD, wintypes.DWORD, wintypes.PHANDLE]
    logon_user_func.restype = wintypes.BOOL

    user = "dummy_user"
    domain = "dummy_domain"
    pwd = "dummy_pwd"
    logon_type = 2
    provider = 0
    handle = wintypes.HANDLE()
    ret = logon_user_func(user, domain, pwd, logon_type, provider, ctypes.byref(handle))
    print("{:s} returned {:}".format(logon_user_func.__name__, "TRUE" if ret else "FALSE"))


if __name__ == "__main__":
    print("Python {:s} on {:s}\n".format(sys.version, sys.platform))
    main()

注意事项：

• 除了argtypes/restypes：
  • 在Python3中，字符串默认为宽，因此不需要encode()
  • HANDLE通过byref传递

输出：

(py35x64_test) e:\Work\Dev\StackOverflow\q051251086>"e:\Work\Dev\VEnvs\py35x64_test\Scripts\python.exe" code.py
Python 3.5.4 (v3.5.4:3f56838, Aug  8 2017, 02:17:05) [MSC v.1900 64 bit (AMD64)] on win32

LogonUserW returned FALSE