Pandas计划忽略时间范围

Question

假设我有一分钟的数据，在三天的营业时间从早上8点到下午4点。我想用pandas绘图函数绘制这些数据：

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt

np.random.seed(51723)
dates = pd.date_range("11/8/2018", "11/11/2018", freq = "min")
df = pd.DataFrame(np.random.rand(len(dates)), index = dates, columns = ['A'])
df = df[(df.index.hour >= 8) & (df.index.hour <= 16)]  # filter for business hours

fig, ax = plt.subplots()
df.plot(ax = ax)
plt.show()

但是，plot函数也在绘图中包含过夜时间，这会导致在此期间意外绘制：

我会连续绘制数据，忽略过夜时间（类似这样）：

什么是一个好的方法，只规划上午8点到下午4点的预定时间？在

Answer 1

这可以通过在不同的轴上绘制每个日期来完成。但像标签这样的东西在某些情况下会变得局促。在

import datetime
import matplotlib.pyplot as plt

pdates = np.unique(df.index.date)  # Unique Dates 

fig, ax = plt.subplots(ncols=len(pdates), sharey=True, figsize=(18,6))

# Adjust spacing between suplots 
# (Set to 0 for continuous, though labels will overlap)
plt.subplots_adjust(wspace=0.05)

# Plot all data on each subplot, adjust the limits of each accordingly
for i in range(len(pdates)):
    df.plot(ax=ax[i], legend=None)
    # Hours 8-16 each day:
    ax[i].set_xlim(datetime.datetime.combine(pdates[i], datetime.time(8)), 
                   datetime.datetime.combine(pdates[i], datetime.time(16)))

    # Deal with spines for each panel
    if i !=0:
        ax[i].spines['left'].set_visible(False)
        ax[i].tick_params(right=False,
                  which='both',
                  left=False,
                  axis='y')
    if i != len(pdates)-1:
        ax[i].spines['right'].set_visible(False)
plt.show()