2024-04-26 12:42:39 发布
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如何将绝对url传递给django函数并重定向到它?在
def function(request): back_url = request.META['HTTP_REFERER'] # example.com/home/?status=80&page=1 return redirect(back_url)
您可以:
def func(request): url = request.META['HTTP_REFERER'] if request.META['QUERY_STRING']: url += '?%s' % request.META['QUERY_STRING'] return redirect_to(request, url, **kwargs)
您可以:
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