from threading import Timer
class Watchdog:
def __init__(self, timeout, userHandler=None): # timeout in seconds
self.timeout = timeout
self.handler = userHandler if userHandler is not None else self.defaultHandler
self.timer = Timer(self.timeout, self.handler)
self.timer.start()
def reset(self):
self.timer.cancel()
self.timer = Timer(self.timeout, self.handler)
self.timer.start()
def stop(self):
self.timer.cancel()
def defaultHandler(self):
raise self
如果要确保函数在不到x秒的时间内完成,请使用:
watchdog = Watchdog(x)
try:
# do something that might take too long
except Watchdog:
# handle watchdog error
watchdog.stop()
如果您定期执行某些内容,并希望确保至少每y秒执行一次,请使用:
import sys
def myHandler():
print "Whoa! Watchdog expired. Holy heavens!"
sys.exit()
watchdog = Watchdog(y, myHandler)
def doSomethingRegularly():
# make sure you do not return in here or call watchdog.reset() before returning
watchdog.reset()
signal.alarm()
为程序设置超时,您可以在主循环中调用它,并将其设置为准备容忍的两次中的较大一次:只是发布我自己的解决方案:
如果要确保函数在不到
x
秒的时间内完成,请使用:如果您定期执行某些内容,并希望确保至少每
y
秒执行一次,请使用:相关问题 更多 >
编程相关推荐